Find the equation of the line in slope intercept form parallel to 5æ + 6y = – 2 and goes through the point (6, – 3) y =

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Question
**Problem Statement:**

Find the equation of the line in slope-intercept form parallel to \( 5x + 6y = -2 \) and goes through the point \((6, -3)\).

**Solution:**

To find the equation of the desired line, we first need to determine the slope of the given line \( 5x + 6y = -2 \). We can rewrite this equation in slope-intercept form \( y = mx + b \), where \( m \) is the slope.

1. **Rearrange the given equation:**

   \[
   6y = -5x - 2
   \]

   \[
   y = -\frac{5}{6}x - \frac{1}{3}
   \]

   The slope of the given line is \( m = -\frac{5}{6} \).

2. **Since parallel lines have the same slope, the slope of the line we need to find is also \( m = -\frac{5}{6} \).**

3. **Use the point-slope form to find the equation of the new line:**

   The point-slope form is \( y - y_1 = m(x - x_1) \), where \((x_1, y_1)\) is the point the line passes through.

   Substituting \( m = -\frac{5}{6} \), \( x_1 = 6 \), and \( y_1 = -3 \):

   \[
   y + 3 = -\frac{5}{6}(x - 6)
   \]

   \[
   y + 3 = -\frac{5}{6}x + 5
   \]

   \[
   y = -\frac{5}{6}x + 5 - 3
   \]

   \[
   y = -\frac{5}{6}x + 2
   \]

   Therefore, the equation of the line in slope-intercept form is:

   \[
   y = -\frac{5}{6}x + 2
   \]
Transcribed Image Text:**Problem Statement:** Find the equation of the line in slope-intercept form parallel to \( 5x + 6y = -2 \) and goes through the point \((6, -3)\). **Solution:** To find the equation of the desired line, we first need to determine the slope of the given line \( 5x + 6y = -2 \). We can rewrite this equation in slope-intercept form \( y = mx + b \), where \( m \) is the slope. 1. **Rearrange the given equation:** \[ 6y = -5x - 2 \] \[ y = -\frac{5}{6}x - \frac{1}{3} \] The slope of the given line is \( m = -\frac{5}{6} \). 2. **Since parallel lines have the same slope, the slope of the line we need to find is also \( m = -\frac{5}{6} \).** 3. **Use the point-slope form to find the equation of the new line:** The point-slope form is \( y - y_1 = m(x - x_1) \), where \((x_1, y_1)\) is the point the line passes through. Substituting \( m = -\frac{5}{6} \), \( x_1 = 6 \), and \( y_1 = -3 \): \[ y + 3 = -\frac{5}{6}(x - 6) \] \[ y + 3 = -\frac{5}{6}x + 5 \] \[ y = -\frac{5}{6}x + 5 - 3 \] \[ y = -\frac{5}{6}x + 2 \] Therefore, the equation of the line in slope-intercept form is: \[ y = -\frac{5}{6}x + 2 \]
Expert Solution
Step 1

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.

5x+6y=-2

solve for y

6y=-5x-2

y=\frac{-5x-2}{6}

y=-\frac{5}{6}x-\frac{2}{6}

y=-\frac{5}{6}x-\frac{1}{3}

here coefficient of x is -5/6

so the slope of the given line is m=-\frac{5}{6}

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