Find the equation of the line given by the intersection of the following two planes: T1:-2x + 4y- z+ 2=0; T2: 3r+2y – z = 1.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Problem:**

Find the equation of the line given by the intersection of the following two planes:

\( \pi_1: -2x + 4y - z + 2 = 0 \)

\( \pi_2: 3x + 2y - z = 1 \)

**Solution Overview:**

To find the equation of the line of intersection, we need to solve the system of linear equations represented by the two plane equations. This will give us a parametric form of the line, often expressed as:

\[ \mathbf{r}(t) = \mathbf{r_0} + t\mathbf{d} \]

where \( \mathbf{r_0} \) is a point on the line and \( \mathbf{d} \) is the direction vector.

**Detailed Explanation:**

1. **Setting up the System of Equations:**
   - The plane equations can be rewritten as:
     - \( -2x + 4y - z = -2 \)
     - \( 3x + 2y - z = 1 \)

2. **Subtracting the Plane Equations:**
   - By eliminating \( z \) through subtraction, we can simplify these equations:
     \[
     (3x + 2y - z) - (-2x + 4y - z) = 1 + 2
     \]
     \[
     3x + 2y - z + 2x - 4y + z = 3
     \]
     \[
     5x - 2y = 3
     \]

3. **Solving for One Variable:**
   - From \( 5x - 2y = 3 \), express one variable in terms of the other, e.g., solve for \( x \):
     \[
     x = \frac{3 + 2y}{5}
     \]

4. **Substitute Back:**
   - Substitute \( x = \frac{3 + 2y}{5} \) into one of the original plane equations to solve for \( z \).

5. **Parameterization:**
   - Assign a parameter, \( t \), for one of the free variables, obtaining the parametric equations of the line:
     \[
     x = f(t), \quad y = g(t), \quad z = h(t)
Transcribed Image Text:**Problem:** Find the equation of the line given by the intersection of the following two planes: \( \pi_1: -2x + 4y - z + 2 = 0 \) \( \pi_2: 3x + 2y - z = 1 \) **Solution Overview:** To find the equation of the line of intersection, we need to solve the system of linear equations represented by the two plane equations. This will give us a parametric form of the line, often expressed as: \[ \mathbf{r}(t) = \mathbf{r_0} + t\mathbf{d} \] where \( \mathbf{r_0} \) is a point on the line and \( \mathbf{d} \) is the direction vector. **Detailed Explanation:** 1. **Setting up the System of Equations:** - The plane equations can be rewritten as: - \( -2x + 4y - z = -2 \) - \( 3x + 2y - z = 1 \) 2. **Subtracting the Plane Equations:** - By eliminating \( z \) through subtraction, we can simplify these equations: \[ (3x + 2y - z) - (-2x + 4y - z) = 1 + 2 \] \[ 3x + 2y - z + 2x - 4y + z = 3 \] \[ 5x - 2y = 3 \] 3. **Solving for One Variable:** - From \( 5x - 2y = 3 \), express one variable in terms of the other, e.g., solve for \( x \): \[ x = \frac{3 + 2y}{5} \] 4. **Substitute Back:** - Substitute \( x = \frac{3 + 2y}{5} \) into one of the original plane equations to solve for \( z \). 5. **Parameterization:** - Assign a parameter, \( t \), for one of the free variables, obtaining the parametric equations of the line: \[ x = f(t), \quad y = g(t), \quad z = h(t)
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