Find the equation of the hyperbola with vertices (-2,5) and (-2, 1) and foci (-2, 12) and (-2,-6). Select the correct answer below: (x+2)² 4 (x+2)² 4 (x-2)² 4 (y+3)² 77 (y+3)² 77 (y-3)² 4 - 1 (y+3)² 77 (y-3)² 77 (y+3)² 77 (x-2)² 4 (x+2)² 4 (x+2)² 77 = 1 = 1 = 1 = 1 = 1 = 1

Q: The parabola y = ² is changed to the form y = a (x − p)² + g by translating the parabola 2 units…

A: The parabola y=x2 is changed to the form y=ax-p2+q by translating the parabola 2 units down and 3…

Q: Find the equation of the hyperbola with vertices (-7,3) and (1, 3) and foci (-11, 3) and (5,3).…

A: Vertices   -7,3 and     (1,3)Foci                -11,3     and   5,3

Q: 3. Find the vertex for the parabola 4x + 2y² + 8 = 0. (a) (0, -2) (b) (-2,0) (c) (2, 2) (d) (-2,1)

A: The equation of the parabola is  4x+2y2+8=0

Q: Find the location of the center, vertices, and foci for the hyperbola described by the equation.…

A: Properties of Hyperbolas Solution:

Q: ←+++ -10-9-8-7 Y 10- g 8+ 77 6 (0,3√5) 5+ 4+ 3+ -5- -7- -8+ 1 2 -6-(0,-3√5) -10- 3 4 5 ++ ++ x 6 7 8…

A:

Q: Is the student's analysis correct? Why or why not? Select all correct statements. The analysis is…

A: This is in fact a hyperboloid of two sheets.The standard equation of which is given by .Now the…

Q: Arrange the parabolas represented by the equations according to the positions of their foci on the…

A: The standard form of a parabola is  (x – h)2 = a(y – k) where (h, k) is the vertex.

Q: Graph the hyperbola (y+3)2/16-(x+6)2/4=1

A: The given equation is (y+3)2/16-(x+6)2/4=1.