Find the equation of the ellipsoid passing through the points (+8, 0, 0), (0₁ +3,0) and (0,0₁ +4)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Problem Statement**

Find the equation of the ellipsoid passing through the points \( (±8, 0, 0), (0, ±9, 0), (0, 0, ±4) \).

**Solution Approach**

To determine the equation of the ellipsoid, we use the standard form:

\[
\frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1
\]

Given points include:

1. \( (±8, 0, 0) \) implies \( \frac{8^2}{a^2} = 1 \), hence \( a^2 = 8^2 = 64 \).

2. \( (0, ±9, 0) \) implies \( \frac{9^2}{b^2} = 1 \), hence \( b^2 = 9^2 = 81 \).

3. \( (0, 0, ±4) \) implies \( \frac{4^2}{c^2} = 1 \), hence \( c^2 = 4^2 = 16 \).

Thus, the equation of the ellipsoid is:

\[
\frac{x^2}{64} + \frac{y^2}{81} + \frac{z^2}{16} = 1
\]
Transcribed Image Text:**Problem Statement** Find the equation of the ellipsoid passing through the points \( (±8, 0, 0), (0, ±9, 0), (0, 0, ±4) \). **Solution Approach** To determine the equation of the ellipsoid, we use the standard form: \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} + \frac{z^2}{c^2} = 1 \] Given points include: 1. \( (±8, 0, 0) \) implies \( \frac{8^2}{a^2} = 1 \), hence \( a^2 = 8^2 = 64 \). 2. \( (0, ±9, 0) \) implies \( \frac{9^2}{b^2} = 1 \), hence \( b^2 = 9^2 = 81 \). 3. \( (0, 0, ±4) \) implies \( \frac{4^2}{c^2} = 1 \), hence \( c^2 = 4^2 = 16 \). Thus, the equation of the ellipsoid is: \[ \frac{x^2}{64} + \frac{y^2}{81} + \frac{z^2}{16} = 1 \]
**Problem Statement:**

Find the equation of the ellipsoid passing through the points \((\pm 8, 0, 0)\), \( (0, \pm 3, 0) \), and \((0, 0, \pm 4)\).
Transcribed Image Text:**Problem Statement:** Find the equation of the ellipsoid passing through the points \((\pm 8, 0, 0)\), \( (0, \pm 3, 0) \), and \((0, 0, \pm 4)\).
Expert Solution
Step 1

We need to find the equation of ellipsoid passing through the points ±8, 0, 0, 0, ±3, 0, 0, 0, ±4.

We know that an ellipsoid has the general equation, x2a2+y2b2+z2c2=1 where a, b and c are the principal semiaxes.

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