Find the equation of the curve whose y" y = sin¯¹(x) — ²√³x - T - 3 6 y = y = sin¯¹(x) - I 2√3 3 y = sin-¹(x) √3 4 6 = 2 sin ¹(x) - 4√3 #+4√3 6 *+6√3 24 I T-V 6 = I (1-x²)3/2 and has a critical point at (1, -3).
Find the equation of the curve whose y" y = sin¯¹(x) — ²√³x - T - 3 6 y = y = sin¯¹(x) - I 2√3 3 y = sin-¹(x) √3 4 6 = 2 sin ¹(x) - 4√3 #+4√3 6 *+6√3 24 I T-V 6 = I (1-x²)3/2 and has a critical point at (1, -3).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
28
Transcribed Image Text:Find the equation of the curve whose y"
y = sin¯¹(x) — ²√³x -
T
-
3
6
y =
y =
sin¯¹(x) - I
2√3
3
y =
sin-¹(x) √3
4
6
= 2 sin ¹(x) -
4√3
#+4√3
6
*+6√3
24
I
T-V
6
=
I
(1-x²)3/2
and has a critical point at (1, -3).
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