28 Find the equation of the curve whose y"y = sin¯¹(x) — ²√³x -T-36y =y =sin¯¹(x) - I2√33y =sin-¹(x) √346= 2 sin ¹(x) -4√3#+4√36*+6√324IT-V6=I(1-x²)3/2and has a critical point at (1, -3).

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Answered: Find the equation of the curve whose y"…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Find the equation of the curve whose y" y = sin¯¹(x) — ²√³x - T - 3 6 y = y = sin¯¹(x) - I 2√3 3 y = sin-¹(x) √3 4 6 = 2 sin ¹(x) - 4√3 #+4√3 6 *+6√3 24 I T-V 6 = I (1-x²)3/2 and has a critical point at (1, -3).