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Find the equation of the circle with center at (3, -7) and diameter equal to 4 points 8 units. * x? + y? – 6x + 14y - 6 = 0. x2 + y? – 6x + 7y + 42 = 0. O Option 3 Option 1 x² + y? – 6x + 14y + 42 = 0. x? + y? + 6x – 14y + 42 = 0. O Option 4 Option 2

Find the equation of the circle with center at (3, -7) and diameter equal to 4 points 8 units. * x? + y? – 6x + 14y - 6 = 0. x2 + y? – 6x + 7y + 42 = 0. O Option 3 Option 1 x² + y? – 6x + 14y + 42 = 0. x? + y? + 6x – 14y + 42 = 0. O Option 4 Option 2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the equation of the circle with center at (3. -7) and diameter equal to 4 points 8 units. * x? + y? – 6x + 14y - 6 = 0. x² + y? – 6x + 7y + 42 = 0. Option 3 Option 1 x' + y? – 6x + 14y + 42 = 0. x? + y? + 6x – 14y + 42 = 0. Option 4 Option 2 None of these
Transcribed Image Text:Find the equation of the circle with center at (3. -7) and diameter equal to 4 points 8 units. * x? + y? – 6x + 14y - 6 = 0. x² + y? – 6x + 7y + 42 = 0. Option 3 Option 1 x' + y? – 6x + 14y + 42 = 0. x? + y? + 6x – 14y + 42 = 0. Option 4 Option 2 None of these
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