Find the equation of the circle below in standard form. Use the magnifying glass in the lower right con to see a larger graph.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the equation
**Instructions:**

Find the equation of the circle below in standard form. Use the magnifying glass in the lower right corner to see a larger graph.

**Graph Description:**

The graph shows a circle on a coordinate plane. The circle is centered at the point (3, -2). The radius of the circle extends 5 units from the center. The grid is marked with horizontal and vertical lines, each representing one unit. The circle is outlined in purple, and its center is marked with a purple dot. 

**Task:**

Based on this information, the standard form of the equation for a circle is \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius. 

In this case, substitute \(h\) with 3, \(k\) with -2, and \(r\) with 5 to find the equation.
Transcribed Image Text:**Instructions:** Find the equation of the circle below in standard form. Use the magnifying glass in the lower right corner to see a larger graph. **Graph Description:** The graph shows a circle on a coordinate plane. The circle is centered at the point (3, -2). The radius of the circle extends 5 units from the center. The grid is marked with horizontal and vertical lines, each representing one unit. The circle is outlined in purple, and its center is marked with a purple dot. **Task:** Based on this information, the standard form of the equation for a circle is \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius. In this case, substitute \(h\) with 3, \(k\) with -2, and \(r\) with 5 to find the equation.
### Graph of a Circle

#### Description:
The image shows a graph with a circle centered at (4, -2) on a Cartesian coordinate plane. 

#### Details:
- **Center of the Circle**: The circle is centered at the point (4, -2), marked by a purple dot.
- **Radius**: The circle has a radius of 5 units, as can be inferred from the distance between the center (4, -2) and any point on the circle's edge, such as (9, -2).
- **Axes**:
  - **X-axis**: Ranges from -10 to 10.
  - **Y-axis**: Ranges from -10 to 10.

#### Key Understanding:
A circle's equation can be represented as \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius. For this particular circle, the equation can be written as \((x-4)^2 + (y+2)^2 = 25\).

This visualization helps understand the relationship between the radius, center, and the overall geometry of a circle on a graph.
Transcribed Image Text:### Graph of a Circle #### Description: The image shows a graph with a circle centered at (4, -2) on a Cartesian coordinate plane. #### Details: - **Center of the Circle**: The circle is centered at the point (4, -2), marked by a purple dot. - **Radius**: The circle has a radius of 5 units, as can be inferred from the distance between the center (4, -2) and any point on the circle's edge, such as (9, -2). - **Axes**: - **X-axis**: Ranges from -10 to 10. - **Y-axis**: Ranges from -10 to 10. #### Key Understanding: A circle's equation can be represented as \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius. For this particular circle, the equation can be written as \((x-4)^2 + (y+2)^2 = 25\). This visualization helps understand the relationship between the radius, center, and the overall geometry of a circle on a graph.
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