Find the equation of a plane containing point R(1,0,1) and parallel to the plane 2x-y+z=1. a direction vector for the given plane is v=<2,-1,1> a plane that is parallel to this plane will have a direction vector that is a scalar multiple of v so we can choose 1 as that multiple, so a plane that is parallel to the given plane that contains the given point is: 2(x-1)-(y-0)+(z-1)=0 2x-2-y+z-1=0 2x-y+z=3 is that correct?