Find the equation of a plane containing point R(1,0,1) and parallel to the plane 2x-y+z=1. a direction vector for the given plane is v=<2,-1,1> a plane that is parallel to this plane will have a direction vector that is a scalar multiple of v so we can choose 1 as that multiple, so a plane that is parallel to the given plane that contains the given point is: 2(x-1)-(y-0)+(z-1)=0 2x-2-y+z-1=0 2x-y+z=3 is that correct?
Find the equation of a plane containing point R(1,0,1) and parallel to the plane 2x-y+z=1. a direction vector for the given plane is v=<2,-1,1> a plane that is parallel to this plane will have a direction vector that is a scalar multiple of v so we can choose 1 as that multiple, so a plane that is parallel to the given plane that contains the given point is: 2(x-1)-(y-0)+(z-1)=0 2x-2-y+z-1=0 2x-y+z=3 is that correct?
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the equation of a plane containing point R(1,0,1) and parallel to the plane 2x-y+z=1.
a direction vector for the given plane is v=<2,-1,1>
a plane that is parallel to this plane will have a direction vector that is a scalar multiple of v so we can choose 1 as that multiple, so a plane that is parallel to the given plane that contains the given point is:
2(x-1)-(y-0)+(z-1)=0
2x-2-y+z-1=0
2x-y+z=3
is that correct?
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