Find the equation of a circle whose diameter ends at (-1,3) & (5,-1). O (x-3)* + (y-2)° = 52 O (x-3)" + (y-2) = 13 O «-2* + (y-1)* = 52 O (x-2)° + (y-1) = 13
Find the equation of a circle whose diameter ends at (-1,3) & (5,-1). O (x-3)* + (y-2)° = 52 O (x-3)" + (y-2) = 13 O «-2* + (y-1)* = 52 O (x-2)° + (y-1) = 13
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Question
![Find the equation of a circle whose diameter ends at (-1,3) & (5,-1).
O (x-3)° + (y-2) = 52
O (x-3)" + (y-2) = 13
O x-2)* + (y-1)* = 52
O (x-2)° + (y-1) = 13](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0fce4705-8e69-4bfb-8424-f2ede2be77f1%2F06894085-ff2a-4a59-9cd1-ebc7d6a2b7a3%2Fukesab_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the equation of a circle whose diameter ends at (-1,3) & (5,-1).
O (x-3)° + (y-2) = 52
O (x-3)" + (y-2) = 13
O x-2)* + (y-1)* = 52
O (x-2)° + (y-1) = 13
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