Find the equation for the tangent plane and the normal line at the point Po(3,1,3) on the surface x + 3y + 2z² = Using a coefficient of 1 for x, the equation for the tangent plane is Find the equations for the normal line. Let x = 3+ 6t. x=0, y=D z= (Type expressions using t as the variable.)

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Q: Find equations of the tangent lines to the curve y²-xy-6=0 at the points (-1,2), and (-1,-3).

A: Given curve: We have to find the equations of the tangent line to the curve  at the points  and