Find the equation for the tangent plane and the normal line at the point Po(1,2,1) on the surface 4x² + y² + 2z² = 10. Using a coefficient of 2 for x, the equation for the tangent plane is. Find the equations for the normal line. Let x = 1 + 8t. X = =, y=, z= (Type expressions using t as the variable.)

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Q: 5y " –(y')* = y³ sin æ

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Q: Find the length of the following curve. y = 2x + 4 on 3-2, 24 (Use calculus.)

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Q: Imeter) Y ( meter) POINT 1 1254,72 2951,76 2 1362,50 3205,13 3 1578,94 3713,80 4 1843,68 4335,92

A: A table of data is given, and the general equation of a line is y=ax+b. Here, a is the slope, and b…

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A: A straight line parallel to x-axis have slope 0.

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Q: Find the distance from the point (4, 9) to the line y = 2x.

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Q: Find the slope of the tangent line to the curve - 322 + 2xy – 3y° - 88 at the point (– 4, 2).

A: The given curve -3x2+2xy-3y3=-88 at the point (-4,2)