Find the equation for the plane through the point P = (0,4, − 1) and normal to the vector n = 2i-7j - k. Choose the correct answer below. OA. 2x-7y-z = 0 OB. 2x-7(y + 4)-(z-1)=0 OC. (x+2)+4(y-7) −1(z − 1) = -27 D. 2x-7y-z = -27

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I'm actually not sure how to solve this.

Q1 Find an equation for the plane through the points (−4,−2,0),(−6,−6,2) and (−7,0,−4). Enter your answer in general or scalar form.(refer the image to screenshot) And Also find the distance between the point (0,−4,1) and the above plane. d=