Find the electric field in N/C for the situation in problem 22.67 on the x-axis at x = 4.18 m
Find the electric field in N/C for the situation in problem 22.67 on the x-axis at x = 4.18 m
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Question
Find the electric field in N/C for the situation in
problem 67 on the x-axis at x = 4,18 m
![QUESTION 5
Find the electric field in N/C for the situation in
problem 22.67 on the x-axis at x = 4.18 m
1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe8e4ba9c-f4e2-4406-a528-e4a92bd942c6%2Fd0756d7c-38fe-4212-a8d5-d66a4cb12ecc%2Fvce264t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 5
Find the electric field in N/C for the situation in
problem 22.67 on the x-axis at x = 4.18 m
1
![articles
67 A charge (uniform linear density = 9.0 nC/m) lies on a string
that is stretched along an x axis from x = 0 to x = 3.0 m. Determine
the magnitude of the electric field at x = 4.0 m on the x axis.
00](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe8e4ba9c-f4e2-4406-a528-e4a92bd942c6%2Fd0756d7c-38fe-4212-a8d5-d66a4cb12ecc%2Fsrtoeee_processed.jpeg&w=3840&q=75)
Transcribed Image Text:articles
67 A charge (uniform linear density = 9.0 nC/m) lies on a string
that is stretched along an x axis from x = 0 to x = 3.0 m. Determine
the magnitude of the electric field at x = 4.0 m on the x axis.
00
Expert Solution
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Introduction:
Electric field at a point can be defined as force acting on unit positive test charge kept at that position. It is a vector quantity. In finding the electric field due to charged string, we take a small charge element on string and find field due to it. We then find the total field by integrating over whole length.
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