Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: PE - dA = EA = Since, its the line charge we use the area of a cylinder surrounding the line charge E*2T L= But all the charged get enclosed by the cylinder area, so Genc = Q Deriving, we get: E 1/2 πεο * IrL)
Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: PE - dA = EA = Since, its the line charge we use the area of a cylinder surrounding the line charge E*2T L= But all the charged get enclosed by the cylinder area, so Genc = Q Deriving, we get: E 1/2 πεο * IrL)
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![Find the electric field everywhere of an infinite uniform line charge with total charge Q.
Sol.
Using Gauss's Law:
EA =
| E0
Since, its the line charge we use the area of a cylinder surrounding the line charge
E*2T
L=
| E0
But all the charged get enclosed by the cylinder area, so
denc = Q
Deriving, we get:
E = (1/2 TEO )*(
/rL)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F86162901-a6b8-4437-9b2d-6941a880380f%2F67aeae29-86c0-44af-87d4-8e18008c9696%2Fkrs8nui_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the electric field everywhere of an infinite uniform line charge with total charge Q.
Sol.
Using Gauss's Law:
EA =
| E0
Since, its the line charge we use the area of a cylinder surrounding the line charge
E*2T
L=
| E0
But all the charged get enclosed by the cylinder area, so
denc = Q
Deriving, we get:
E = (1/2 TEO )*(
/rL)
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