Find the domain of the function: In (9 – x2) Use the properties of logarithms to write the expression as a single logarithm: In (x) – In (x² – 1) Use the change of base formula and a calculator to find the solution: log37 (round to 3 places)

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Chapter6: Vector Spaces
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### Calculus and Algebra Practice Problems

#### 1. Evaluate the expression **ln e**
The natural logarithm of \( e \) (where \( e \) is the base of the natural logarithms, approximately equal to 2.71828) is 1. Therefore, \( \ln e = 1 \).

#### 2. Find the domain of the function: \( \ln(9 - x^2) \)
To determine the domain of the function \( \ln(9 - x^2) \), we need the argument of the logarithm (i.e., \( 9 - x^2 \)) to be greater than 0:
\[ 9 - x^2 > 0 \]
\[ 9 > x^2 \]
\[ -3 < x < 3 \]
Thus, the domain is \( -3 < x < 3 \).

#### 3. Use the properties of logarithms to write the expression as a single logarithm: \( \ln(x) - \ln(x^2 - 1) \)
Using the properties of logarithms, specifically the difference of logarithms property (\( \ln(a) - \ln(b) = \ln(\frac{a}{b}) \)):
\[ \ln(x) - \ln(x^2 - 1) = \ln\left(\frac{x}{x^2 - 1}\right) \]

#### 4. Use the change of base formula and a calculator to find the solution: \( \log_3 7 \) (round to 3 places)
The change of base formula for logarithms is given by:
\[ \log_b a = \frac{\ln(a)}{\ln(b)} \]
Using this formula:
\[ \log_3 7 = \frac{\ln(7)}{\ln(3)} \]
Using a calculator to compute:
\[ \log_3 7 \approx \frac{1.945910}{1.098612} \approx 1.771 \]
Thus, \( \log_3 7 \approx 1.771 \) (rounded to 3 decimal places).
Transcribed Image Text:### Calculus and Algebra Practice Problems #### 1. Evaluate the expression **ln e** The natural logarithm of \( e \) (where \( e \) is the base of the natural logarithms, approximately equal to 2.71828) is 1. Therefore, \( \ln e = 1 \). #### 2. Find the domain of the function: \( \ln(9 - x^2) \) To determine the domain of the function \( \ln(9 - x^2) \), we need the argument of the logarithm (i.e., \( 9 - x^2 \)) to be greater than 0: \[ 9 - x^2 > 0 \] \[ 9 > x^2 \] \[ -3 < x < 3 \] Thus, the domain is \( -3 < x < 3 \). #### 3. Use the properties of logarithms to write the expression as a single logarithm: \( \ln(x) - \ln(x^2 - 1) \) Using the properties of logarithms, specifically the difference of logarithms property (\( \ln(a) - \ln(b) = \ln(\frac{a}{b}) \)): \[ \ln(x) - \ln(x^2 - 1) = \ln\left(\frac{x}{x^2 - 1}\right) \] #### 4. Use the change of base formula and a calculator to find the solution: \( \log_3 7 \) (round to 3 places) The change of base formula for logarithms is given by: \[ \log_b a = \frac{\ln(a)}{\ln(b)} \] Using this formula: \[ \log_3 7 = \frac{\ln(7)}{\ln(3)} \] Using a calculator to compute: \[ \log_3 7 \approx \frac{1.945910}{1.098612} \approx 1.771 \] Thus, \( \log_3 7 \approx 1.771 \) (rounded to 3 decimal places).
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