Find the distance between the two points * A) 2V5 C) 2V2 B) 2v10 D) 4V2

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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**Question:**

Find the distance between the two points *

[Insert image showing a graph with two points plotted and a right triangle illustrated]

The graph depicts a Cartesian coordinate system with the x-axis labeled from -4 to 4 and the y-axis labeled similarly.

Two points are marked on the graph:
- The first point is at (0, 2)
- The second point is at (4, -2)

These points are connected by a straight line, and a right triangle is formed by drawing a horizontal line from (0, 2) to (4, 2) and a vertical line from (4, 2) to (4, -2).

The length of the horizontal leg of the triangle measures 4 units, and the length of the vertical leg measures 4 units.

Using the Pythagorean theorem to find the distance between the two points:
\[ \text{Distance} = \sqrt{(4 - 0)^2 + (2 - (-2))^2} \]
\[ = \sqrt{4^2 + 4^2} \]
\[ = \sqrt{16 + 16} \]
\[ = \sqrt{32} \]
\[ = 4\sqrt{2} \]

**Answer Choices:**
A) \( 2\sqrt{5} \)
B) \( 2\sqrt{10} \)
C) \( 2\sqrt{2} \)
D) \( 4\sqrt{2} \)

The correct answer is: **D) \( 4\sqrt{2} \)**

---

**Explanation of Diagram:**

The diagram is a graph showing two points and a right triangle whose hypotenuse is the line segment connecting the two points. The horizontal and vertical distances are labeled, showing 4 units each. By calculating the hypotenuse using the Pythagorean theorem, the distance between the two points is determined to be \( 4\sqrt{2} \).
Transcribed Image Text:**Question:** Find the distance between the two points * [Insert image showing a graph with two points plotted and a right triangle illustrated] The graph depicts a Cartesian coordinate system with the x-axis labeled from -4 to 4 and the y-axis labeled similarly. Two points are marked on the graph: - The first point is at (0, 2) - The second point is at (4, -2) These points are connected by a straight line, and a right triangle is formed by drawing a horizontal line from (0, 2) to (4, 2) and a vertical line from (4, 2) to (4, -2). The length of the horizontal leg of the triangle measures 4 units, and the length of the vertical leg measures 4 units. Using the Pythagorean theorem to find the distance between the two points: \[ \text{Distance} = \sqrt{(4 - 0)^2 + (2 - (-2))^2} \] \[ = \sqrt{4^2 + 4^2} \] \[ = \sqrt{16 + 16} \] \[ = \sqrt{32} \] \[ = 4\sqrt{2} \] **Answer Choices:** A) \( 2\sqrt{5} \) B) \( 2\sqrt{10} \) C) \( 2\sqrt{2} \) D) \( 4\sqrt{2} \) The correct answer is: **D) \( 4\sqrt{2} \)** --- **Explanation of Diagram:** The diagram is a graph showing two points and a right triangle whose hypotenuse is the line segment connecting the two points. The horizontal and vertical distances are labeled, showing 4 units each. By calculating the hypotenuse using the Pythagorean theorem, the distance between the two points is determined to be \( 4\sqrt{2} \).
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