Find the distance between the point and the plane. (4, 3, 2) x - y + 5z = 8 Step 1 The distance between a plane and a point Q not in the plane is given by the following formula |v• n| ||n|| D where P is a point in the plane, n is normal to the plane, and v is the vector from P to Q. Let P = (8, 0, 0) and let Q = (4, 3, 2). Find v. v = (-4 V -4 3 V 3, 2 V 2) Step 2 Find an appropriate normal vector n. n = (1 |-1 , 5 5 ) |-1 Step 3 Use your results from Part 1 and Part 2 to find D, the distance between the given point and plane. D =

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter2: Functions And Graphs
Section2.2: The Rectangular Coordinate System And Graphing Lines
Problem 120E
Question
Find the distance between the point and the plane.
(4, 3, 2)
x - y + 5z = 8
Step 1
The distance between a plane and a point Q not in the plane is given by the following formula
|v• n|
||n||
D
where P is a point in the plane, n is normal to the plane, and v is the vector from P to Q.
Let P = (8, 0, 0) and let Q = (4, 3, 2). Find v.
v = (-4 V
-4
3 V
3, 2 V
2)
Step 2
Find an appropriate normal vector n.
n = (1
|-1 , 5
5 )
|-1
Step 3
Use your results from Part 1 and Part 2 to find D, the distance between the given point and plane.
D =
Transcribed Image Text:Find the distance between the point and the plane. (4, 3, 2) x - y + 5z = 8 Step 1 The distance between a plane and a point Q not in the plane is given by the following formula |v• n| ||n|| D where P is a point in the plane, n is normal to the plane, and v is the vector from P to Q. Let P = (8, 0, 0) and let Q = (4, 3, 2). Find v. v = (-4 V -4 3 V 3, 2 V 2) Step 2 Find an appropriate normal vector n. n = (1 |-1 , 5 5 ) |-1 Step 3 Use your results from Part 1 and Part 2 to find D, the distance between the given point and plane. D =
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