Find the direction for which the directional derivative of g(x, y) = 4x – xy + 2y² at (-2, 3) is a maximum. What is the unit vector, u, for which Du is maximized, and what is the value of Dy? Select the correct answer below: V197 14 197 ' 197 u = , Du = 14 =(197 197), VT97 Du = V197 14V197 u = Du = V197 197 197 14V197 u = , Du = 197 %3D 197' 197

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
Find the direction for which the directional derivative of g(x, y) = 4x – xy + 2y² at (–2, 3) is a maximum. What is the unit
vector, u, for which Du is maximized, and what is the value of Du?
Select the correct answer below:
V197 14
197 ' 197
u =
, Du = 14
(197 197), Da = V197
u =
V197 14V197
u =
Du = V197
197
197
14/T97
197' 197
u =
, Du = 197
Transcribed Image Text:Find the direction for which the directional derivative of g(x, y) = 4x – xy + 2y² at (–2, 3) is a maximum. What is the unit vector, u, for which Du is maximized, and what is the value of Du? Select the correct answer below: V197 14 197 ' 197 u = , Du = 14 (197 197), Da = V197 u = V197 14V197 u = Du = V197 197 197 14/T97 197' 197 u = , Du = 197
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