Find the differential equation y(x – 1)dx – (x² – 2x – 2y)dy = 0 a.x² + 2x + 4 = 2Cy² b.x² + 2x + 4y = 2Cy² с.х2 + 2х — 4у %3 2Су? d.x2 — 2х — 4у %3D2Су? - - 4y = e. None of the above - |

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