Find the difference quotient, f(x+h)-f(x)/h where h is not equal to zero of the function f(x) =2x+1 a. 2 b. 2+2/h c. 0 d. 2+(4(x+1/h)) Find the difference quotient, f(x+h)-f(x)/h where h is not equal to zero of the function f(x) x^2-2x a. 2x-h+1 b. 2x-h-1 c. 2x+h-2 d. 2x+h+2

Q: Find the domain of the function : f(x) = 1/(x + 7) + 3/(x - 9).

A:

Q: let f(x) =4x+3 and g(x) =5x-2. find the function. f-g

A: Topic:- function

Q: Differentiate: y = (2a° – 4x² + 8)* (2² – 5e³*)²

A: Product Rule of Differentiation : ddx(uv) = ddx(u) · v + u · ddx(v)

Q: Is f (x) = (3x - 2) - (2x + 1) a linear function? Explain your answer.

A: To check: Whether the given function is linear or not. Given information: The function is…

Q: Evaluate the function for fx) = x + 3 and g(x) = x2 – 2. (fg)(8) (fg)(8) =

A: The functions f(x)=x+3 and g(x)=x2-2. We have to find fg8=?

Q: Let f(x) = 3x³ - 8x² + 4x + 6. Find f(0). f(0) =

A: we are given the function and we need to find out the value of the function at x=0.

Q: If f(x)=7x-10, find f-1(18)

A: Since f is a linear function therefore to find the required value we need to find the value of x for…

Q: Consider f(x) = 3x4 −16x3 +24x2 −9. sketch the function

A: We have to sketch the given function.

Q: Do f(x) = 2x2 - 1 and h(t) = 2t2 - 1 represent the same function? why or why not

A: The two given functions are

Q: 7) Determine when the function f(x) = 6x - 35x +56x - 20 is positive and when it's negative.

A: The given function is: f(x)=6x3-35x2+56x-20

Q: Let f(x) = x - x. What is the simplest form of , h70? h

A: Please refer to the image below

Q: Evaluate f +3 /1+x4 3 dx.

A:

Q: Let f(x) = 3-4x. Find f(-2). f(-2)% =

A: Let f(x) = 3 - 4x, We have to find the value of f(-2)

Q: Let f(x) = x² + 5x and g(x) = 4 – x. Find (-2). (- 2) = (Simplify your answer.) %3D

A: As the domain of both f(x) and g(x) is R. (f/g)(x) = f(x)/g(x).

Q: Let f(x) = 2x + 3x? + 5x + 5. Find f(3 + V2).

A:

Q: find a so that the domain of the function f(x) = -5x +sqrt{a-x^2} is (-3,3) a. 3 b. 9 c. -9 d.…

A: