Find the difference quotient and simplify your answer. Ax) = x² – x + 1, f(6 + h) – f(6) -, h+0 h f(6 + h) – f(6) = h + 12, h# 0 h f(6 + h) – f(6) = h + 13, h+ 0 h f(6 + h) – f(6) = h + 14, h+ 0 h f(6 + h) – f(6) = h + 15, h+ 0 h f(6 + h) – f(6) = h + 11, h± 0 h
Find the difference quotient and simplify your answer. Ax) = x² – x + 1, f(6 + h) – f(6) -, h+0 h f(6 + h) – f(6) = h + 12, h# 0 h f(6 + h) – f(6) = h + 13, h+ 0 h f(6 + h) – f(6) = h + 14, h+ 0 h f(6 + h) – f(6) = h + 15, h+ 0 h f(6 + h) – f(6) = h + 11, h± 0 h
Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Functions
Section9.S: Summary
Problem 4S
Related questions
Question
![Find the difference quotient and simplify your answer.
f(6 + h) – f(6)
Ax) = x2 – x+ 1,
-, h+0
h
f(6 + h) – f(6)
= h + 12, h+ 0
h
f(6 + h) – f(6)
= h + 13, h+0
%3D
h
f(6 + h) – f(6)
= h + 14, h± 0
h
f(6 + h) – f(6)
= h + 15, h+ 0
%3D
h
f(6 + h) – f(6)
h + 11, h+ 0
h](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8686dac3-4f6e-4646-84e4-ae4e8d8b3051%2F87932238-83d7-4d03-b41a-7d5b29e07a5c%2Feeaplfv_processed.png&w=3840&q=75)
Transcribed Image Text:Find the difference quotient and simplify your answer.
f(6 + h) – f(6)
Ax) = x2 – x+ 1,
-, h+0
h
f(6 + h) – f(6)
= h + 12, h+ 0
h
f(6 + h) – f(6)
= h + 13, h+0
%3D
h
f(6 + h) – f(6)
= h + 14, h± 0
h
f(6 + h) – f(6)
= h + 15, h+ 0
%3D
h
f(6 + h) – f(6)
h + 11, h+ 0
h
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