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Find the difference quotient and simplify your answer. Ax) = x² – x + 1, f(6 + h) – f(6) -, h+0 h f(6 + h) – f(6) = h + 12, h# 0 h f(6 + h) – f(6) = h + 13, h+ 0 h f(6 + h) – f(6) = h + 14, h+ 0 h f(6 + h) – f(6) = h + 15, h+ 0 h f(6 + h) – f(6) = h + 11, h± 0 h

Find the difference quotient and simplify your answer. Ax) = x² – x + 1, f(6 + h) – f(6) -, h+0 h f(6 + h) – f(6) = h + 12, h# 0 h f(6 + h) – f(6) = h + 13, h+ 0 h f(6 + h) – f(6) = h + 14, h+ 0 h f(6 + h) – f(6) = h + 15, h+ 0 h f(6 + h) – f(6) = h + 11, h± 0 h

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the difference quotient and simplify your answer. f(6 + h) – f(6) Ax) = x2 – x+ 1, -, h+0 h f(6 + h) – f(6) = h + 12, h+ 0 h f(6 + h) – f(6) = h + 13, h+0 %3D h f(6 + h) – f(6) = h + 14, h± 0 h f(6 + h) – f(6) = h + 15, h+ 0 %3D h f(6 + h) – f(6) h + 11, h+ 0 h
Transcribed Image Text:Find the difference quotient and simplify your answer. f(6 + h) – f(6) Ax) = x2 – x+ 1, -, h+0 h f(6 + h) – f(6) = h + 12, h+ 0 h f(6 + h) – f(6) = h + 13, h+0 %3D h f(6 + h) – f(6) = h + 14, h± 0 h f(6 + h) – f(6) = h + 15, h+ 0 %3D h f(6 + h) – f(6) h + 11, h+ 0 h
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