Find the derivative y = ecotx Ody da Ody dx Ody dx dy -ecotx csc²x = cotx csc²x ecotx csc²x cotx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
**Problem Statement:**

Find the derivative \( y = e^{\cot x} \).

**Answer Choices:**

1. \(\frac{dy}{dx} = -e^{\cot x} \csc^2 x\)
   
2. \(\frac{dy}{dx} = \cot x \csc^2 x\)

3. \(\frac{dy}{dx} = e^{\cot x} \csc^2 x\)

4. \(\frac{dy}{dx} = -e^{\cot x}\)

**Explanation:**

To find the correct derivative, apply the chain rule. The derivative of the \(e^{u}\) function is \(e^{u} \cdot \frac{du}{dx}\), where \(u = \cot x\).

The derivative of \(\cot x\) is \(-\csc^2 x\), so:

\[
\frac{dy}{dx} = e^{\cot x} \cdot (-\csc^2 x) = -e^{\cot x} \csc^2 x
\]

Therefore, the correct answer is:

1. \(\frac{dy}{dx} = -e^{\cot x} \csc^2 x\)
Transcribed Image Text:**Problem Statement:** Find the derivative \( y = e^{\cot x} \). **Answer Choices:** 1. \(\frac{dy}{dx} = -e^{\cot x} \csc^2 x\) 2. \(\frac{dy}{dx} = \cot x \csc^2 x\) 3. \(\frac{dy}{dx} = e^{\cot x} \csc^2 x\) 4. \(\frac{dy}{dx} = -e^{\cot x}\) **Explanation:** To find the correct derivative, apply the chain rule. The derivative of the \(e^{u}\) function is \(e^{u} \cdot \frac{du}{dx}\), where \(u = \cot x\). The derivative of \(\cot x\) is \(-\csc^2 x\), so: \[ \frac{dy}{dx} = e^{\cot x} \cdot (-\csc^2 x) = -e^{\cot x} \csc^2 x \] Therefore, the correct answer is: 1. \(\frac{dy}{dx} = -e^{\cot x} \csc^2 x\)
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