Find the derivative: y = (3x² – 2x) Væ5 – 2x + 2 %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the derivative:
y = (3x²
– 2x) Væ5 – 2x + 2
dy
(32 -2a) (5æ* –2)
+ (x5 – 2x + 2) (6x – 2)
-
dx
2 5 –2x+2
dy
27x6+15x4 –15x²+30x-8
dx
V5 –2x+2
dy
276 –14x5 –30x²+36x-8
da
2 æ5 –2x+2
dy
(32² –2æ) (5æª –2)
+ Væ5 – 2x + 2
dx
2/5 –2x+2
O (E) None of the choices
||
Transcribed Image Text:Find the derivative: y = (3x² – 2x) Væ5 – 2x + 2 dy (32 -2a) (5æ* –2) + (x5 – 2x + 2) (6x – 2) - dx 2 5 –2x+2 dy 27x6+15x4 –15x²+30x-8 dx V5 –2x+2 dy 276 –14x5 –30x²+36x-8 da 2 æ5 –2x+2 dy (32² –2æ) (5æª –2) + Væ5 – 2x + 2 dx 2/5 –2x+2 O (E) None of the choices ||
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