Find the derivative of y= (2x³+x+1) 4(x²+3)5 (x4+3) 3 O A dy (4) (2x³+x+1) ³ (5) (x²+3) 4 dx 2(x²+3) ² OB. dy (2x³+x+1) 4(x²+3) 5 4 5 dx (x²+3) 3 2x³+x+1 x²+3 x++3 C dy (2x³+x+1)+(x²+3) 5 24x²+4 10x 12x3 (x++3)³ 2x³+x+1 x²+3 OD dy 13 dx CE None of these 11 4 2x³ +x+1 +3 T + + 33 x²4 4
Find the derivative of y= (2x³+x+1) 4(x²+3)5 (x4+3) 3 O A dy (4) (2x³+x+1) ³ (5) (x²+3) 4 dx 2(x²+3) ² OB. dy (2x³+x+1) 4(x²+3) 5 4 5 dx (x²+3) 3 2x³+x+1 x²+3 x++3 C dy (2x³+x+1)+(x²+3) 5 24x²+4 10x 12x3 (x++3)³ 2x³+x+1 x²+3 OD dy 13 dx CE None of these 11 4 2x³ +x+1 +3 T + + 33 x²4 4
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![Find the derivative of
y=
(2x³+x+1) 4(x²+3)5
(x4+3) 3
OA dy (4) (2x³+x+1)³(5) (x²+3)4
dx
2(x²+3) ²
OB. dy
(2x³+x+1) 4(x²+3) 5
4
5
dx
(x²+3) 3
2x³+x+1 x²+3 x+3
C. dy (2x³+x+1)+(x²+3) 5 24x2+4
10x
12x3
(x²+3) ³
2x³+x+1 x²+3
13
=
11
4
2x³ +x+1
dx
CE None of these
+3
T
+
33
x²4
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc0f7cc9-058c-4420-b4c2-0bfb103b906f%2F384fd19f-9769-448c-8269-8091accbb806%2Fk839o3n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the derivative of
y=
(2x³+x+1) 4(x²+3)5
(x4+3) 3
OA dy (4) (2x³+x+1)³(5) (x²+3)4
dx
2(x²+3) ²
OB. dy
(2x³+x+1) 4(x²+3) 5
4
5
dx
(x²+3) 3
2x³+x+1 x²+3 x+3
C. dy (2x³+x+1)+(x²+3) 5 24x2+4
10x
12x3
(x²+3) ³
2x³+x+1 x²+3
13
=
11
4
2x³ +x+1
dx
CE None of these
+3
T
+
33
x²4
4
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