Find the derivative of the given function. Fill the missing expressions. Use logarithmic differentiation. y = x• secx Vx² + 1 Step 1. Take the absolute value of both sides. lyl = x• secx · /x2 + 1 Step 2. Take the natural logarithm of both sides. In ]y| = In x· secx /x² + 1 secx · Step 3. Expand using the properties of Logarithm Inly| = Inx + In|secx| + Step 4. Differentiate both sides. 1 D,(Inlyl) = D, [Inx + In|secx| + In(x² + 1)] 1 1 .· Dz(secx) + 1 D,(x² + 1) 2 x2 + 1 1 = -+ 1 secx tanx + 1 2x 2 x2 + 1 Step 5. Multiply both sides of the equation by y to solve for y' ' = y · (- tanx + (x2 + 1)) Step 6. Substitute y with the given function. y' 1 + 5cotx + 3(x +1) (1 – x2),

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