Find the derivative of the function. <-2 g(x) = (7x² - - ² 4 4x + 7 g'(x) = 2 ((7x²-4) (28x² +98x-16)) (4x+7)³ Need Help? Read It -3 X

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the derivative of the function.

\[ g(x) = \left( \frac{7x^2 - 4}{4x + 7} \right)^{-2} \]

The expression for \( g'(x) \) (the derivative of \( g(x) \)) is given as:

\[ g'(x) = 2 \cdot \left( \frac{\left( (7x^2 - 4)(28x^2 + 98x - 16) \right)}{(4x + 7)^3} \right)^{-3} \]

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Transcribed Image Text:### Assignment Scoring **Your last submission is used for your score.** ### 5. [0/1 Points] --- #### Problem Details Find the derivative of the function. \[ g(x) = \left( \frac{7x^2 - 4}{4x + 7} \right)^{-2} \] The expression for \( g'(x) \) (the derivative of \( g(x) \)) is given as: \[ g'(x) = 2 \cdot \left( \frac{\left( (7x^2 - 4)(28x^2 + 98x - 16) \right)}{(4x + 7)^3} \right)^{-3} \] --- ### Need Help? **Read It** --- **Submit Answer Button** --- **Navigation** **View Previous**
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