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Find the derivative of the function. h(e)- (-1) ( 1) +]

Find the derivative of the function. h(e)- (-1) ( 1) +]

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Solve for step 3
25 The Chain Rule (9/2. X Ahttps://www.webassign.net/web/Student/Assignment-Responses/submit?dep-270589348tags autosavequestion47ro8s53 8 Find the derivative of the function. h(t)- (-1) (t+ 1)6 Step 1 The function h(t) = (t - 1)°( + 1)6 is a product, and so we must use the Product Rule to find its derivative. Also, the factors of the product are compositions, so finding their derivatives will require using the Chain Rule. Using the Chain Rule, the derivative of (t - 1)5 is 4 . +4 -1 Step 2 Similarly, the derivative of (t3 + 1)6 is +1 t3 +1 Step 3 Using these derivatives in the Product Rule, we get h'(t) = (t4 – 1)5(6( After factoring and simplifying, we can conclude that the derivative is as follows. 201 (A – 1)4 h'(t) = Type here to search
Transcribed Image Text:25 The Chain Rule (9/2. X Ahttps://www.webassign.net/web/Student/Assignment-Responses/submit?dep-270589348tags autosavequestion47ro8s53 8 Find the derivative of the function. h(t)- (-1) (t+ 1)6 Step 1 The function h(t) = (t - 1)°( + 1)6 is a product, and so we must use the Product Rule to find its derivative. Also, the factors of the product are compositions, so finding their derivatives will require using the Chain Rule. Using the Chain Rule, the derivative of (t - 1)5 is 4 . +4 -1 Step 2 Similarly, the derivative of (t3 + 1)6 is +1 t3 +1 Step 3 Using these derivatives in the Product Rule, we get h'(t) = (t4 – 1)5(6( After factoring and simplifying, we can conclude that the derivative is as follows. 201 (A – 1)4 h'(t) = Type here to search
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Given ht=t4-15t3+16

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