Find the derivative of the function. G'(x) = G(x)=√1-169x² arccos(13x) -168x V1-169x arccos (13x) - 13 X Enhanced Feedback Please try again. Remember to use the product and chain rules. Recall that arccos(x) = 1-x²

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3.6 Q4

Find the derivative of the function.
G(x)=√1 - 169x² arccos(13x)
-168x
G'(x) = √1-169x²
-arccos (13x) - 13
X
Enhanced Feedback
dx
Please try again. Remember to use the product and chain rules. Recall that arccos(x):
==
1
1- +²
Transcribed Image Text:Find the derivative of the function. G(x)=√1 - 169x² arccos(13x) -168x G'(x) = √1-169x² -arccos (13x) - 13 X Enhanced Feedback dx Please try again. Remember to use the product and chain rules. Recall that arccos(x): == 1 1- +²
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