Find the derivative of the function. 1 y = 4/x +3x dy dx |00 %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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4.1 #4 Pt3
**Problem Statement:**

Find the derivative of the function.

\[ y = 4\sqrt{x} + 3x^{\frac{1}{8}} \]

---

**Solution:**

To find the derivative \(\frac{dy}{dx}\) of the given function, break down each term separately:

1. **Derivative of \(4\sqrt{x}\):**

   Recall that \(\sqrt{x} = x^{\frac{1}{2}}\).

   \[
   \frac{d}{dx}[4x^{\frac{1}{2}}] = 4 \cdot \frac{1}{2}x^{\frac{1}{2}-1} = 2x^{-\frac{1}{2}}
   \]

   Simplifying further:

   \[
   2x^{-\frac{1}{2}} = \frac{2}{\sqrt{x}}
   \]

2. **Derivative of \(3x^{\frac{1}{8}}\):**

   \[
   \frac{d}{dx}[3x^{\frac{1}{8}}] = 3 \cdot \frac{1}{8}x^{\frac{1}{8}-1} = \frac{3}{8}x^{-\frac{7}{8}}
   \]

By combining the derivatives of both terms, we have:

\[
\frac{dy}{dx} = \frac{2}{\sqrt{x}} + \frac{3}{8}x^{-\frac{7}{8}}
\]

The box for \(\frac{dy}{dx}\) is left for further input or checking the solution as needed.
Transcribed Image Text:**Problem Statement:** Find the derivative of the function. \[ y = 4\sqrt{x} + 3x^{\frac{1}{8}} \] --- **Solution:** To find the derivative \(\frac{dy}{dx}\) of the given function, break down each term separately: 1. **Derivative of \(4\sqrt{x}\):** Recall that \(\sqrt{x} = x^{\frac{1}{2}}\). \[ \frac{d}{dx}[4x^{\frac{1}{2}}] = 4 \cdot \frac{1}{2}x^{\frac{1}{2}-1} = 2x^{-\frac{1}{2}} \] Simplifying further: \[ 2x^{-\frac{1}{2}} = \frac{2}{\sqrt{x}} \] 2. **Derivative of \(3x^{\frac{1}{8}}\):** \[ \frac{d}{dx}[3x^{\frac{1}{8}}] = 3 \cdot \frac{1}{8}x^{\frac{1}{8}-1} = \frac{3}{8}x^{-\frac{7}{8}} \] By combining the derivatives of both terms, we have: \[ \frac{dy}{dx} = \frac{2}{\sqrt{x}} + \frac{3}{8}x^{-\frac{7}{8}} \] The box for \(\frac{dy}{dx}\) is left for further input or checking the solution as needed.
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Use formulas of derivatives to find dy/dx

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