Find the derivative of f(x) = log, (x° + x – 1). %3D 2 + x - 1 f (2) = %3D (3z* + 1) (In 2) (3z +1) (In 2) f '(z) = ,3 %3D + x - 1 (2 +x – 1) (In 2) f '(z) = 3a +1 +a - 1 f (z): (3z +1) (6z) (In 2) 3x +1 'f (z) = %3D (z +z - 1) (In 2)
Find the derivative of f(x) = log, (x° + x – 1). %3D 2 + x - 1 f (2) = %3D (3z* + 1) (In 2) (3z +1) (In 2) f '(z) = ,3 %3D + x - 1 (2 +x – 1) (In 2) f '(z) = 3a +1 +a - 1 f (z): (3z +1) (6z) (In 2) 3x +1 'f (z) = %3D (z +z - 1) (In 2)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Find the derivative of \( f(x) = \log_2 (x^3 + x - 1) \).
1. \( f'(x) = \frac{x^3 + x - 1}{(3x^2 + 1)(\ln 2)} \)
2. \( f'(x) = \frac{(3x^2 + 1)(\ln 2)}{x^3 + x - 1} \)
3. \( f'(x) = \frac{(x^3 + x - 1)(\ln 2)}{3x^2 + 1} \)
4. \( f'(x) = \frac{x^3 + x - 1}{(3x^2 + 1)(6x)(\ln 2)} \)
5. \( f'(x) = \frac{3x^2 + 1}{(x^3 + x - 1)(\ln 2)} \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9af8275-1771-4259-b36c-229c128dc795%2F2cf12edd-1ae7-421d-bec4-c05ad6d625dd%2Fzdi7hum_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the derivative of \( f(x) = \log_2 (x^3 + x - 1) \).
1. \( f'(x) = \frac{x^3 + x - 1}{(3x^2 + 1)(\ln 2)} \)
2. \( f'(x) = \frac{(3x^2 + 1)(\ln 2)}{x^3 + x - 1} \)
3. \( f'(x) = \frac{(x^3 + x - 1)(\ln 2)}{3x^2 + 1} \)
4. \( f'(x) = \frac{x^3 + x - 1}{(3x^2 + 1)(6x)(\ln 2)} \)
5. \( f'(x) = \frac{3x^2 + 1}{(x^3 + x - 1)(\ln 2)} \)
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