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Find the derivative at each critical point and determine the local extreme values. y = x(4 - x²)

Find the derivative at each critical point and determine the local extreme values. y = x(4 - x²)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the derivative at each critical point and determine the local extreme values. y = x(4 - x2) Select one: A. Critical Pt. derivative Extremum/Value x= 1.15 x= -1.15 0 local max 3.08 local min -3.08 B. Critical Pt derivative Extremum|Value |local max -6.16 local min 3.08 C. Critical Pt. derivative (Extremum/Value local max -6.16 local min | 3.0S D. Critical Pt. derivative Extremum|Value 3.08 x = -1.15 0 x = 1.15 x= 1.15 10 x= -1.15 0 x= -1.15 0 |local max x= 1.15 local min -6.16
Transcribed Image Text:Find the derivative at each critical point and determine the local extreme values. y = x(4 - x2) Select one: A. Critical Pt. derivative Extremum/Value x= 1.15 x= -1.15 0 local max 3.08 local min -3.08 B. Critical Pt derivative Extremum|Value |local max -6.16 local min 3.08 C. Critical Pt. derivative (Extremum/Value local max -6.16 local min | 3.0S D. Critical Pt. derivative Extremum|Value 3.08 x = -1.15 0 x = 1.15 x= 1.15 10 x= -1.15 0 x= -1.15 0 |local max x= 1.15 local min -6.16
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