Find the degree measure of arc AW. 6x + 16 W A 85°

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Finding the Degree Measure of Arc AW**

**Diagram Explanation:**

- The diagram is a circle divided by lines into four arcs: \( AW, WC, CB, \) and \( BA \).
- \( W \) is the point at the top of the circle.
- \( A \) is the point on the left of the circle.
- \( C \) is the point on the right of the circle.
- \( B \) is the point at the bottom of the circle.
- \( D \) is the center of the circle, and the angle at \( D \) inside the circle connected to \( CB \) is given as \( 85^\circ \).

**Given Information:**

- Arc \( AW \) is represented by the expression \( 6x + 16 \) degrees.
- Arc \( CB \) is represented by the expression \( 10 + 10x \) degrees.

**Problem Statement:**

You need to find the degree measure of arc \( AW \).

**Solution Steps:**

1. Understand that the sum of angles around point \( D \) in a circle is always \( 360^\circ \).
2. Set up the equation including all arc measures around the circle:
   \[
   6x + 16 + 85 + (10 + 10x) = 360
   \]
3. Combine like terms:
   \[
   6x + 10x + 16 + 85 + 10 = 360
   \]
   \[
   16x + 111 = 360
   \]
4. Solve for \( x \):
   \[
   16x = 360 - 111
   \]
   \[
   16x = 249
   \]
   \[
   x = \frac{249}{16}
   \]
   \[
   x = 15.5625
   \]
5. Substitute \( x \) back into the expression for arc \( AW \):
   \[
   AW = 6x + 16
   \]
   \[
   AW = 6(15.5625) + 16
   \]
   \[
   AW = 93.375 + 16
   \]
   \[
   AW = 109.375
   \]

**Conclusion:**

The degree measure of arc \( AW \) is
Transcribed Image Text:--- **Finding the Degree Measure of Arc AW** **Diagram Explanation:** - The diagram is a circle divided by lines into four arcs: \( AW, WC, CB, \) and \( BA \). - \( W \) is the point at the top of the circle. - \( A \) is the point on the left of the circle. - \( C \) is the point on the right of the circle. - \( B \) is the point at the bottom of the circle. - \( D \) is the center of the circle, and the angle at \( D \) inside the circle connected to \( CB \) is given as \( 85^\circ \). **Given Information:** - Arc \( AW \) is represented by the expression \( 6x + 16 \) degrees. - Arc \( CB \) is represented by the expression \( 10 + 10x \) degrees. **Problem Statement:** You need to find the degree measure of arc \( AW \). **Solution Steps:** 1. Understand that the sum of angles around point \( D \) in a circle is always \( 360^\circ \). 2. Set up the equation including all arc measures around the circle: \[ 6x + 16 + 85 + (10 + 10x) = 360 \] 3. Combine like terms: \[ 6x + 10x + 16 + 85 + 10 = 360 \] \[ 16x + 111 = 360 \] 4. Solve for \( x \): \[ 16x = 360 - 111 \] \[ 16x = 249 \] \[ x = \frac{249}{16} \] \[ x = 15.5625 \] 5. Substitute \( x \) back into the expression for arc \( AW \): \[ AW = 6x + 16 \] \[ AW = 6(15.5625) + 16 \] \[ AW = 93.375 + 16 \] \[ AW = 109.375 \] **Conclusion:** The degree measure of arc \( AW \) is
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