find the deflection for B2 (point C TO F) using AMM (Area Moment Diagram) KGCA1.20 mHDB-4B-3B-26.3 mB-19.0 mE1.50 mL4.20 m4.20 mF4.20 mB Reactions:EM₁ = 0C10 x 0.6 + 26.82 × 1·2+29.25 × 7-56:3³)+ (16-25×9) (²1) - V₁ × 9 = 0V₁ = 143.92 KN+ 10 × 8·25+ (10·84 × 6·3) (1- 2 + 6≤ Fy= 0VVF-10-26.82-29-25-10- 10.84 x 6-3-V₂90.37= 146.69 KN16.25 x 9 = 0Calculations:=shear Force(just to the left = JLSE= 146.69 KNSFM (JL) = 146.69 -16.25 × 0·6 = 136.94 KNSFM (JR) = 146.69-10 · 16 · 25 × 0·6 = 126.94 KNSF₂ (JL) = 126-94-16.25x0.6 = 117.19 KNSF₂ (JR) = 117.19 - 26.82 = 90.37 KNKNSFE (JL) = 40.37 - 10.84 × 6.3 -16.25 x 6-3 = -80.3SEE (JR) = -80.3 - 29.25 = 109.55 KNSF (JL) = -109.55 - 16-25 x0.75=-121.74 KNSF (JR) = -121-74-10 = -131-74 KNSFF16.25 KNm80.36.3-4с= -131-74- 16.25 × 0·75 = -143.92 KN10 KN⇒x= 3·336mJust to the right = JR)|VcM D0.6m146.6926.82 KN1.2m136.94126.947117-19१०.37C M D85.09+158.33с mp10.84 KN/m(FBD309-1+(6.3-x)29-25KN80.3$109-55E6.3mof Beam B-2) VE10 KNN0.75mK-5mE N121.747131.74119011FE NFSFD(KN)143.92103.37BMD(KN-m)F

In case of Area moment method, First of all, draw the M/EI diagram of the beam. Then always try to…

Answered: find the deflection for B2 (point C TO…

Engineering

Civil Engineering

find the deflection for B2 (point C TO F) using AMM (Area Moment Diagram)

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter3: Tension Members

Section: Chapter Questions

Problem 3.3.1P

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