Find the Cyclomatic Complexity of the following code segment: int average (int[ ] value, int min, int max, int N) { int i, totalValid, sum, mean; i = totalValid = sum = 0; while ( i < N || value[i] != -999 ) { if (value[i] >= min && value[i] <= max){ totalvalid += 1; sum += value[i]; if (totalValid > 0) mean = sum / totalValid; else mean = -999; i += 1; return mean; } The value ofN = 1197 MAX = 16211 %3D Min = 6

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Q1:. 

Find the Cyclomatic Complexity of the following code segment:
int average (int[ ] value, int min, int max, int N) {
int i, totalValid, sum, mean;
i = totalValid = sum = 0;
while ( i < N || value[i] != -999 ) {
if (value[i] >= min && value[i] <= max){
totalvalid += 1; sum += value[i];
if (totalValid > 0)
mean = sum / totalValid;
else
mean = -999;
i += 1;
return mean;
}
The value ofN = 1197
MAX = 16211
Min = 6
Transcribed Image Text:Find the Cyclomatic Complexity of the following code segment: int average (int[ ] value, int min, int max, int N) { int i, totalValid, sum, mean; i = totalValid = sum = 0; while ( i < N || value[i] != -999 ) { if (value[i] >= min && value[i] <= max){ totalvalid += 1; sum += value[i]; if (totalValid > 0) mean = sum / totalValid; else mean = -999; i += 1; return mean; } The value ofN = 1197 MAX = 16211 Min = 6
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