Find the current in the 12-2 resistor in the figure below. (Assume R, = R3 = 1.6 N, R2 = R4 =6.8 Ω, Δν - 12 ν.) A R2 R1 R4 R3 4.0 N 2.0 N 12 N + Δν

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Chapter1: Units, Trigonometry. And Vectors
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**Question:**

Find the current in the 12-Ω resistor in the figure below. (Assume \( R_1 = R_3 = 1.6 \, \Omega \), \( R_2 = R_4 = 6.8 \, \Omega \), \( \Delta V = 12 \, \text{V} \).)

**Diagram Description:**

The circuit diagram shows the following configuration:

- A series circuit with a voltage source (battery) providing \( \Delta V = 12 \, \text{V} \).
- The circuit includes a 12-Ω resistor in series with a 4.0-Ω resistor.
- This series arrangement is parallel to another branch containing two resistors: a 6.8-Ω resistor labeled \( R_2 \) and a 2.0-Ω resistor.
- The parallel combination is connected to a 1.6-Ω resistor labeled \( R_3 \).
- The circuit elements return to the voltage source, completing the loop.

To find the current through the 12-Ω resistor, analyze the equivalent resistance of the circuit and use Ohm's law.
Transcribed Image Text:**Question:** Find the current in the 12-Ω resistor in the figure below. (Assume \( R_1 = R_3 = 1.6 \, \Omega \), \( R_2 = R_4 = 6.8 \, \Omega \), \( \Delta V = 12 \, \text{V} \).) **Diagram Description:** The circuit diagram shows the following configuration: - A series circuit with a voltage source (battery) providing \( \Delta V = 12 \, \text{V} \). - The circuit includes a 12-Ω resistor in series with a 4.0-Ω resistor. - This series arrangement is parallel to another branch containing two resistors: a 6.8-Ω resistor labeled \( R_2 \) and a 2.0-Ω resistor. - The parallel combination is connected to a 1.6-Ω resistor labeled \( R_3 \). - The circuit elements return to the voltage source, completing the loop. To find the current through the 12-Ω resistor, analyze the equivalent resistance of the circuit and use Ohm's law.
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