Find the cumulative distribution function of the random variable X representing the number of defectives in Problem #5. Then using F(x), find (a) P(X = 1); (b) P(0 < X ≤ 2).

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Chapter1: Combinatorial Analysis
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  1. Find the cumulative distribution function of the random variable X representing the number of defectives in Problem #5. Then using F(x), find (a) P(X = 1); (b) P(0 < X ≤ 2).
In order to find the probability distribution of X, we need to find the
probability of X being each of the possible values.
Since there are 2 defective sets and the hotel is purchasing 3 sets,
X can take values 0, 1 and 2.
(i) If X=0 then all 3 purchased sets are among the 5 non-defective television
sets so:
10
| 2
P(X = 0) =
35
(ii) If X=1 then 2 of 3 purchased sets are among the 5 non-defective
television sets, while 1 purchased set is among the 2 defective sets so:
() · G)
10 - 2
P(X = 1) :
35
(iii) If X=2 then 2 of 3 purchased sets are exactly the 2 defective sets, while
the remaining one is non-defective so:
(1) · () _ 5 . 1
P(X = 1) =
G)
35
Transcribed Image Text:In order to find the probability distribution of X, we need to find the probability of X being each of the possible values. Since there are 2 defective sets and the hotel is purchasing 3 sets, X can take values 0, 1 and 2. (i) If X=0 then all 3 purchased sets are among the 5 non-defective television sets so: 10 | 2 P(X = 0) = 35 (ii) If X=1 then 2 of 3 purchased sets are among the 5 non-defective television sets, while 1 purchased set is among the 2 defective sets so: () · G) 10 - 2 P(X = 1) : 35 (iii) If X=2 then 2 of 3 purchased sets are exactly the 2 defective sets, while the remaining one is non-defective so: (1) · () _ 5 . 1 P(X = 1) = G) 35
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