Find the critical values for (a) A left-tailed test with a=0.15 (b) A two-tailed test with a= 0.03
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Find the critical values for
(a) A left-tailed test with a=0.15
(b) A two-tailed test with a= 0.03
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- In a randomized controlled trial conducted with children suffering from viral croup, 46 children were treated with low humidity while 46 other children were treated with high humidity. The low-humidity group had a mean score of 0.98 with a standard deviation of 1.22, while the high-humidity group had a mean score of 1.09 with a standard deviation of 1.11. Use a 0.05 significance level to test the claim that the two groups are from populations with the same mean. (Show solution) A. The null hypothesis is i. The low-humidity group has unequal mean with the high-humidity group. ii. The low-humidity group has greater mean with the high-humidity group. iii. The low-humidity group has equal mean with the high-humidity group. iv. The low-humidity group has less mean with the high-humidity group. B. The computed t-test statistic is i. 0.763 ii. 0.597 iii. 0.452 iv. 0.681 C. The critical/tabular t-test statistic is i. 1.678 ii. 2.013 iii.…Volunteers who had developed a cold within the previous 24 hours were randomized to take either zinc or placebo lozenges every 2 to 3 hours until their cold symptoms were gone. Twenty-five participants took zinc lozenges, and 23 participants took placebo lozenges. The mean overall duration of symptoms for the zinc lozenge group was 4.5 days, and the standard deviation of overall duration of symptoms was 1.4 days. For the placebo group, the mean overall duration of symptoms was 7.8 days, and the standard deviation was 2 days. (a) Calculate a 95% confidence interval for the mean overall duration of symptoms in a population of individuals like those who used the zinc lozenges. (Round your answers to two decimal places.)______ to _____ days(b) Calculate a 95% confidence interval for the mean overall duration of symptoms in a population of individuals like those who used the placebo lozenges. (Round your answers to two decimal places.)______ to _____ daysThe mean number of English courses taken in a two-year time period by male and female college students is believed to be about the same. An experiment is conducted and data are collected from 24 males and 26 females. The males took an average of 4.2 English courses with a standard deviation of 1.1. The females took an average of 3.9 English courses with a standard deviation of 0.7. Conduct a hypothesis test at the 4% level of significance to determine whether the means are statistically the same. Step 1: State the null and alternative hypotheses. Ho: H1 = V H.: H1 – µ2 # v test.) (So we will be performing a two-tailed
- Suppose you are a quality control manager at a manufacturing company that produces light bulbs. The company has recently made changes to the manufacturing process, and you want to investigate whether these changes have had a significant impact on the average lifespan of the bulbs. You collect a random sample of 30 light bulbs produced under the new process and find that the sample mean lifespan is 1200 hours with a sample standard deviation of 100 hours. Additionally, you collect a random sample of 35 light bulbs produced under the old process and find that the sample mean lifespan is 1180 hours with a sample standard deviation of 90 hours. Assuming that the population standard deviations are unknown but equal, test at a 5% significance level that the average lifespan of the light bulb has changed with the new manufacturing process. NOT FOR MARKS, just a book sample questionVolunteers who had developed a cold within the previous 24 hours were randomized to take either zinc or placebo lozenges every 2 to 3 hours until their cold symptoms were gone. Twenty-five participants took zinc lozenges, and 23 participants took placebo lozenges. The mean overall duration of symptoms for the zinc lozenge group was 4.5 days, and the standard deviation of overall duration of symptoms was 1.6 days. For the placebo group, the mean overall duration of symptoms was 8 days, and the standard deviation was 1.8 days. (a) Calculate a 95% confidence interval for the mean overall duration of symptoms in a population of individuals like those who used the zinc lozenges. (Round your answers to two decimal places.)to days(b) Calculate a 95% confidence interval for the mean overall duration of symptoms in a population of individuals like those who used the placebo lozenges. (Round your answers to two decimal places.)to days(c) On the basis of the intervals computed in parts (a) and…A researcher has a first-grade readiness test that is administered to kindergarten students and scored at the interval level. The population mean is 60, with a standard deviation of 10. He has administered it, individually, to a random sample of 58 kindergarten students in a city, M = 66, and wants to use a single-sample z test, two-tailed with α = .05, in order to see whether first-grade readiness in this city differs from the national level. Check the assumptions and decide if it is OK for him to proceed with the single-sample z test.
- "On the Standford-Binet test, the mean IQ is 100. A class of 7 kindergarten pupils were tested with a resulting mean of 103 and a standard deviation of 5.28. Does this group have a mean significantly different than the norm group? Use 0.1 as your level of significance." It is safe to assume that they are within the norm unless additional evidence say otherwise. B "Yes, however, the class is lower than the norm, on average" "Yes, in fact the class is above the norm, on average." D) "No, I am 100% sure that they are within the norm value."You are conducting a study to see if the probability of a true negative on a test for a certain cancer is significantly different from 0.7. Thus you are performing a two-tailed test. Your sample data produce the test statistic 2 = - 1.361. Find the p-value accurate to 4 decimal places. p-value =[third question] *refer to the photo below*
- Plzz solved both question (i and ii) Compulsoury... And explainYou are performing a two-tailed t-test with a sample size of 19If α=0.05, and your test statistic is t=1.69, do you (pick an option): Fail to Reject Null Hypothesis Reject Null HypothesisScores on a certain "IQ" test for 18-25 year olds are normally distributed. A researcher believes that the average IQ score for students at a certain NJ college is less than 110 points, and so wants to test this hypothesis. The researcher obtain a SRS of 45 student IQ scores from school records and found the mean of the 45 results was 108 with a sample standard deviation of 21. The level of significance (alpha) used for this problem is 0.05/ What is the appropriate test statistic (Student must complete by showing by formula using the ap- propriate values in that formula "showing work" and the final answer and appropriate label)? O T test score = (108-110)/(45/sqrt(21)) = -.2037 O I test score = (108-110)/(21/sqrt(45)) = -.639 T test score = (108-110)/(21/sqrt(45)) = .639 I test score = (110-108)/(21/sqrt(45)) = .639
