Find the critical value z that corresponds to the given confidence levels.a. 90%b. 98%

Solution-: We wan to find critical value z that corresponds to the given confidence levels (a) 90%…

Answered: Find the critical value z that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Which statement is true below for the size of the confidence interval for u? O The confidence interval increases as the standard deviation decreases. O The confidence interval increases as the standard deviation increases. O The confidence interval increases as the sample size increases. O The t-value for a confidence interval of 95% is smaller than for a confidence interval of 90%
Determine whether the statement below makes sense or does not make sense. Explain clearly. Based on our sample, the 95% confidence interval for the mean amount of television watched by adults in a nation is 2.9 to 4.3 hours per day. Therefore, there is 95% chance that the mean for all adults in the nation will fall somewhere in this range and a 5% chance that it will not. C Choose the correct answer below. O A. The statement makes sense. There is 5% probability that the confidence interval limits do not contain the true value of the sample mean, so the probability it does not contain the true value of the population mean is also 5%. O B. The statement does not make sense. The population mean is a fixed constant that either falls within the confidence interval or it does not. There is no probability associated with this. O C. The statement does not make sense. The probability the population mean is greater than the upper limit is 5% and the probability it is less than the lower limit is…
You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 13 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 18 12 10 9 15 5 9 6 18 5 17 11 6 a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 13 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of visits per patient and about percent will not contain the true population mean number of visits per patient.
Help.explain.
Calculate the test statistic for the given scenario. Round your answer to 3 decimal places p-p Vpg/n A company claims the 85% of their employees are happy with their work environment. A survey of 50 employees is taken in which 45 say they are happy with their work environment.
You are interested in finding a 90% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 15 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 8 15 5 18 9 28 5 14 23 25 18 20 23 9 16 a. To compute the confidence interval use a distribution. b. With 90% confidence the population mean number of visits per physical therapy patient is between and visits. c. If many groups of 15 randomly selected physical therapy patients are studied, then a different confidence interval would be produced from each group. About ____percent of these confidence intervals will contain the true population mean number of visits per patient and about ____percent will not contain the true population mean number of visits per patient.
Use the formula in this example to determine the sample size, n.The estimated prevalence is 19%, and the desired confidence level is 93% with a margin of error of 4%. (Round your answer to the nearest integer.)n =
You sample 36 students to find out how many hours they spent online last week. Your sample mean is 54. The population standard deviation, sigma, is 8.2. Your client now wants the 90% confidence interval for this sample mean. It is: 40.1 to 67.9 51.8 to 56.2 40.5 to 67.5 51.0 to 56.0
A statistics practitioner took a random sample of 49 observations from a population and computed the sample mean to be 100. For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Suppose the population standard deviation is 28. Estimate the population mean with 95% confidence. Confidence Interval = B. Suppose the population standard deviation is 41. Estimate the population mean with 95% confidence. Confidence Interval = C. Suppose the population standard deviation is 10. Estimate the population mean with 95% confidence. Confidence Interval =
Construct a confidence interval for the population proportion p. n ? 144, x ? 86, 90% confidence
You are estimating how much population A's proportion of answering yes to a question exceeds population B's proportion who say yes to the same question by using a confidence interval. You have some ability to control the width of your interval. Which of the following would be most likely to ensure that the confidence interval is narrowed? O a. You increase both sample sizes and you decrease your confidence level. O b. You increase both sample sizes and you increase your confidence level. OC. You decrease both sample sizes and you increase your confidence level. O d. You decrease both sample sizes and you decrease your confidence level.
Find the first and third quartile for the data shown x 10.3 12.1 14.7 17.3 18.7 19.9 20 27.7 27.8 28.4 Q1 = Q3 =

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Find the critical value z that corresponds to the given confidence levels. a. 90% b. 98%