Find the cotangent of ZH. I 20 16 12 Simplify your answer and write it as a proper fraction, improper fraction, or whole number. cot (H) =
Find the cotangent of ZH. I 20 16 12 Simplify your answer and write it as a proper fraction, improper fraction, or whole number. cot (H) =
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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![### Understanding and Calculating Cotangent in Right Triangles
**Topic**: Precalculus - Finding Trigonometric Ratios Using Right Triangles (Lesson M.5, L6Y)
---
#### Objective:
Find the cotangent of ∠H.
---
#### Diagram:
The image shows a right triangle \( \triangle IHJ \) with:
- side \( IJ = 16 \),
- side \( IH = 20 \),
- side \( JH = 12 \),
- and a right angle at \( \angle J \).
```
I
|\
| \ 20
16| \
| \
|____\
J 12 H
```
#### Instructions:
Simplify your answer and write it as a proper fraction, improper fraction, or whole number.
---
#### Calculation:
\[ \cot(H) = \frac{\text{Adjacent}}{\text{Opposite}} \]
Using the triangle \( \triangle JIH \):
- Adjacent to ∠H is \( JI = 16 \),
- Opposite to ∠H is \( HJ = 12 \).
\[ \cot(H) = \frac{16}{12} = \frac{4}{3} \]
Thus,
\[ \cot(H) = \frac{4}{3} \]
---
Please input the simplified cotangent value:
\[ \cot(H) = \boxed{} \]
---
Click "Submit" once you have entered the value.
### Submit
---
This content will help you understand how to find the cotangent of an angle in right triangles by using the ratios of the sides.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b87147b-e6ac-4544-bb87-4039cb80b5aa%2F129c4628-42b2-4141-a390-9cc103ab1260%2Frqeles_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding and Calculating Cotangent in Right Triangles
**Topic**: Precalculus - Finding Trigonometric Ratios Using Right Triangles (Lesson M.5, L6Y)
---
#### Objective:
Find the cotangent of ∠H.
---
#### Diagram:
The image shows a right triangle \( \triangle IHJ \) with:
- side \( IJ = 16 \),
- side \( IH = 20 \),
- side \( JH = 12 \),
- and a right angle at \( \angle J \).
```
I
|\
| \ 20
16| \
| \
|____\
J 12 H
```
#### Instructions:
Simplify your answer and write it as a proper fraction, improper fraction, or whole number.
---
#### Calculation:
\[ \cot(H) = \frac{\text{Adjacent}}{\text{Opposite}} \]
Using the triangle \( \triangle JIH \):
- Adjacent to ∠H is \( JI = 16 \),
- Opposite to ∠H is \( HJ = 12 \).
\[ \cot(H) = \frac{16}{12} = \frac{4}{3} \]
Thus,
\[ \cot(H) = \frac{4}{3} \]
---
Please input the simplified cotangent value:
\[ \cot(H) = \boxed{} \]
---
Click "Submit" once you have entered the value.
### Submit
---
This content will help you understand how to find the cotangent of an angle in right triangles by using the ratios of the sides.
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