Find the coordinates of the point P on the circumference of the circle. (Hint: Add x- and y-axes, assuming that the angle is in standard position.) 10 The coordinates of P are (Type an ordered pair. Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.) 120°

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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### Finding the Coordinates of a Point on a Circle

To find the coordinates of the point P on the circumference of the circle, follow these steps (Hint: Add x- and y-axes, assuming that the angle is in standard position).

1. **Understanding the Problem:**
    - **Circle Information:** The radius of the circle is 10 units.
    - **Angle Information:** The angle is given as 120 degrees.

2. **Graph Description:**
    - **Diagram:** A circle is drawn with a radius extending from the center to point P.
    - **Radius (r):** The length of the radius is labeled as 10 units.
    - **Angle (θ):** The angle between the radius and the x-axis, measured counterclockwise, is labeled as 120 degrees.

3. **Calculating Coordinates:**
    - **Using Trigonometric Functions:** 
      - The x-coordinate of P can be found using \( x = r \cos(\theta) \).
      - The y-coordinate of P can be found using \( y = r \sin(\theta) \).
    - **Substitute Values:**
      - \( r = 10 \)
      - \( \theta = 120^\circ \)
      - \( x = 10 \cos(120^\circ) \)
      - \( y = 10 \sin(120^\circ) \)
    - **Simplify Using Trigonometric Values:**
      - \(\cos(120^\circ) = -\frac{1}{2} \)
      - \(\sin(120^\circ) = \frac{\sqrt{3}}{2} \)
    - **Final Coordinates:**
      - \( x = 10 \left(-\frac{1}{2}\right) = -5 \)
      - \( y = 10 \left(\frac{\sqrt{3}}{2}\right) = 5\sqrt{3} \)

Therefore, the coordinates of point P are \(\left( -5, 5\sqrt{3} \right)\).

**Boxed Answer:**
\[
\text{The coordinates of P are } \left( -5, 5\sqrt{3} \right).
\]

*(Type an ordered pair. Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)*
Transcribed Image Text:### Finding the Coordinates of a Point on a Circle To find the coordinates of the point P on the circumference of the circle, follow these steps (Hint: Add x- and y-axes, assuming that the angle is in standard position). 1. **Understanding the Problem:** - **Circle Information:** The radius of the circle is 10 units. - **Angle Information:** The angle is given as 120 degrees. 2. **Graph Description:** - **Diagram:** A circle is drawn with a radius extending from the center to point P. - **Radius (r):** The length of the radius is labeled as 10 units. - **Angle (θ):** The angle between the radius and the x-axis, measured counterclockwise, is labeled as 120 degrees. 3. **Calculating Coordinates:** - **Using Trigonometric Functions:** - The x-coordinate of P can be found using \( x = r \cos(\theta) \). - The y-coordinate of P can be found using \( y = r \sin(\theta) \). - **Substitute Values:** - \( r = 10 \) - \( \theta = 120^\circ \) - \( x = 10 \cos(120^\circ) \) - \( y = 10 \sin(120^\circ) \) - **Simplify Using Trigonometric Values:** - \(\cos(120^\circ) = -\frac{1}{2} \) - \(\sin(120^\circ) = \frac{\sqrt{3}}{2} \) - **Final Coordinates:** - \( x = 10 \left(-\frac{1}{2}\right) = -5 \) - \( y = 10 \left(\frac{\sqrt{3}}{2}\right) = 5\sqrt{3} \) Therefore, the coordinates of point P are \(\left( -5, 5\sqrt{3} \right)\). **Boxed Answer:** \[ \text{The coordinates of P are } \left( -5, 5\sqrt{3} \right). \] *(Type an ordered pair. Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)*
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