Find the centripetal acceleration of a person standing on the Earth equator. Consider the radius of the Earth to be 6400000 m and the period of rotation to be 1 day O0 0.043 m/sec2 O0 0.34 m/sec2 0.43 m/sec2

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Find the centripetal acceleration of a
person standing on the Earth equator.
Consider the radius of the Earth to be
6400000 m and the period of rotation to
be 1 day
*
0.043 m/sec2
0.34 m/sec2
0.43 m/sec2
Transcribed Image Text:Find the centripetal acceleration of a person standing on the Earth equator. Consider the radius of the Earth to be 6400000 m and the period of rotation to be 1 day * 0.043 m/sec2 0.34 m/sec2 0.43 m/sec2
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