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Find the center of mass of a lamina in the shape of an isosceles right triangle with equal sides of length a = 30 if the density at any point is proportional to the square of the distance from the vertex opposite the hy- potenuse. Assume the vertex opposite the hypotenuse is located at (0, 0), and that the sides are along the positive axes.

Find the center of mass of a lamina in the shape of an isosceles right triangle with equal sides of length a = 30 if the density at any point is proportional to the square of the distance from the vertex opposite the hy- potenuse. Assume the vertex opposite the hypotenuse is located at (0, 0), and that the sides are along the positive axes.

Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter81: Introduction To Computer Numerical Control (cnc)
Section: Chapter Questions
Problem 4A: A rectangular solid has length L=12.6 mm, width W=23.8 mm, and height H=32.5 mm. Find the length of...
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Find the center of mass of a lamina in the shape of an isosceles right triangle with equal sides of length a = 30 if the density at any point is proportional to the square of the distance from the vertex opposite the hy- potenuse. Assume the vertex opposite the hypotenuse is located at (0, 0), and that the sides are along the positive axes. 1. (18, 18) 2. (14, 14) 3. (6, 6) 4. (12, 12) 5. (8, 8)
Transcribed Image Text:Find the center of mass of a lamina in the shape of an isosceles right triangle with equal sides of length a = 30 if the density at any point is proportional to the square of the distance from the vertex opposite the hy- potenuse. Assume the vertex opposite the hypotenuse is located at (0, 0), and that the sides are along the positive axes. 1. (18, 18) 2. (14, 14) 3. (6, 6) 4. (12, 12) 5. (8, 8)
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