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Find the center and radius of the circle whose equation is x² +92 + y² - 1y - 3 = 0. The center of the circle is Enter the coordinates in decimal form. The radius of the circle is Round the radius if 4 decimal places if needed.

Find the center and radius of the circle whose equation is x² +92 + y² - 1y - 3 = 0. The center of the circle is Enter the coordinates in decimal form. The radius of the circle is Round the radius if 4 decimal places if needed.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the center and radius of the circle whose equation is x² +92 + y² - 1y - 3 = 0. The center of the circle is Enter the coordinates in decimal form. The radius of the circle is Round the radius if 4 decimal places if needed.
Transcribed Image Text:Find the center and radius of the circle whose equation is x² +92 + y² - 1y - 3 = 0. The center of the circle is Enter the coordinates in decimal form. The radius of the circle is Round the radius if 4 decimal places if needed.
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