Find the Boolean expression, in both sum-of-products (SOP) and product-of-sums (POS) forms, for the logic represented by the following truth table. A оооонннн B оонноонн C нонононо Y 1 177 1 0 ооо
Find the Boolean expression, in both sum-of-products (SOP) and product-of-sums (POS) forms, for the logic represented by the following truth table. A оооонннн B оонноонн C нонононо Y 1 177 1 0 ооо
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:### Boolean Expression from Truth Table
Given the task of finding the Boolean expression in both sum-of-products (SOP) and product-of-sums (POS) forms, analyze the provided truth table to understand the logic:
#### Truth Table
| A | B | C | Y |
|---|---|---|---|
| 0 | 0 | 0 | 1 |
| 0 | 0 | 1 | 1 |
| 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 0 | 0 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 0 |
#### Explanation of the Table
- **Columns:** The first three columns represent inputs A, B, and C. The fourth column, Y, represents the output.
- **Rows:** Each row shows a unique combination of inputs and the resulting output.
### Sum-of-Products (SOP) Expression
The SOP expression considers the rows where the output Y is 1 (logical high).
**For this table:**
- Rows 0, 1, 2, and 3 have Y = 1.
**SOP Equation:**
- \( Y = \overline{A} \overline{B} \overline{C} + \overline{A} \overline{B} C + \overline{A} B \overline{C} + \overline{A} B C \)
### Product-of-Sums (POS) Expression
The POS expression is derived by considering rows where the output Y is 0 (logical low).
**For this table:**
- Rows 4, 5, 6, and 7 have Y = 0.
**POS Equation:**
- \( Y = (A + B + C)(A + B + \overline{C})(A + \overline{B} + C)(A + \overline{B} + \overline{C}) \)
These logical expressions are crucial for simplifying complex logic circuits and are used in various digital systems.
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