Find the bending moment for the given diagram. CA = 2m; AB = 6m; BD = 1m Bending moment at A = -2x² - (2x³/27) sub x = CA = 2m = -8.59 KN.m Show complete solutions as well as the solution on how to get bending diagram. Bending Moment diagram for Over hanging beam by MATLAB Overhanging beam means A beam freely supported at two points and having one or both ends extending beyond these supports is termed an overhanging beam. Find bending moment for given diagram: From this diagram CA=2m AB=6m Bending moment at A=-2x^2-(2x^3/27) sub x=CA=2m =-8.59 KN.m BD=1m 1m C 1+2m+ A 6 m- (a) 2 m ABD 14

Find the bending moment for the given diagram. CA = 2m; AB = 6m; BD = 1m Bending moment at A = -2x² - (2x³/27) sub x = CA = 2m = -8.59 KN.m Show complete solutions as well as the solution on how to get bending diagram. Bending Moment diagram for Over hanging beam by MATLAB Overhanging beam means A beam freely supported at two points and having one or both ends extending beyond these supports is termed an overhanging beam. Find bending moment for given diagram: From this diagram CA=2m AB=6m Bending moment at A=-2x^2-(2x^3/27) sub x=CA=2m =-8.59 KN.m BD=1m 1m C 1+2m+ A 6 m- (a) 2 m ABD 14

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Subject: Structural Theory 2 Task: Answer this question in different methods such as Double Integration method, area moment method, conjugate beam method, AND virtual work method.
value of the slope (rotation) at the end of a cantilever beam with a distributed force, w = 8.9kN / m The beam has the following properties: E = 200GPa , I = 467 cm^4 L= 4.8 m.
For the forces acting on the beam shown in Figure 3.1f, determine the location of the equivalent resultant force with reference to point A in m. Given / = 2.4, P1 = 8, P2 = 8 and w = 2 %3D (Note: Prefix the answer with negative sign "." if the location is to the left of the reference point. E.g. if the location of the equivalent resultant is located between points A and B, or to the left of point B by 1.2m, the answer should be "-1.2" with reference to point B) P, kN W kN/m P, kN C 21 m 21 m Figure 3.1f
Problem 2. Use virtual work method and determine the following unknowns on the truss system shown below. Use A = 500 mm² and E = 200 GPa. Show complete and organized solution. Round-off your answers to two decimal places. %3D a. Horizontal displacement of joint G due to the applied loads in mm b. Horizontal displacement of joint G considering that the top chord members experience 60 °C increase in temperature in mm. Use a = 10/ °C A=40.0 70 kN B=5.0 "a" kN C=9.0 50 kN "a" kN "c" m D 4 at "b" m
In the structure shown, the support at A rotates 3x10-3 radians CCW, and the support at C has a settlement of 0.8 inches. Make the shear force and bending moment diagram using 1. Three-moment equation 2. Slope Deflection Method Make sure the diagrams for both methods are the same.
For the forces acting on the beam shown in Figure 3.1f, determine the location of the equivalent resultant force with reference to point B in m. Given / = 1.5, P1 = 5, P2 = 20 and w = 4 (Note: Prefix the answer with negative sign "-" if the location is to the left of the reference point. E.g. if the location of the equivalent resultant is located between points A and B, or to the left of point B by 1.2m, the answer should be "-1.2" with reference to point B) P, kN W kN/m |P2 kN 21 m 21 m Figure 3.1f
Q1: The horizontal rigid beam ABCD is supported by vertical bars BE and CF and is loaded by vertical forces P = 400 kN and P2 = 360 kN acting at points A and D, respectively (see figure). Bars BE and CF are made of steel (E = 200 GPa) and have cross-sectional areas ABE = 11,100 mm² and Acp = 9,280 mm². The distances between various points on the bars are shown in the figure. Determine the vertical displacements &, and ôp of points A and D, respectively. E1.5m 1.5 m 2.1 m – A P = 400 kN 2.4 m P2 = 360 kN F 0.6 m|
Problem: Analyze the continuous beam shown in Figure by drawing the shear and bending moment diagram and sketch the elastic curve. 10 ft AB 1.2 k/ft 30 ft 60 k ↓ 20 ft 10 ft 40 k 15 ft 5 ft E
A part of slab is given in the figure. The slab is supported by secondary beams AB, CD and EF which are placed with a 50cm spacing. The secondary beams transfer the load they carry to the main beams.In the figure, AE and FB are the visible part of the main beams. Finally, main beams are supported by the columns at both ends. The slab is under uniformly distributed load q=4.5 kN/m2. The span length L is 3,5 m. Determine the dimendions of rectengular cross-sections of timber beams CD and the main beam which has a length of 4 m.
Solve the problem by the moment-area method. The beam has constant flexural rigidity EI. A simple beam AB supports two concentrated loads P at the positions shown in the figure. B C 4. 4 A support C at the midpoint of the beam is positioned at distance d below the beam before the loads are applied. Assuming that d = 12 mm, L = 5.4 m, E = 200 GPa, and I = 193 x 10° mm, calculate the magnitude of the loads P (in kN) so that the beam just touches the support at C. 163.87 x kN
A beam supported by three identical springs at points A,B,C (see figure). Given that flexural of rigidity of the beam, EI= 2.029X1011 N.mm2 ; spring constant,k = 1471.5N/mm, w=116N/mm All dimensions are in mm. 1. What is the reaction for at point A,B and C? 2. What is the deflection at point B? 3. Please draw shear-force and bending moment diagram.