Find the area under the standard normal curve between the given z-values. Round your answer to four decimal places, if necessary. z1=−2.06, z2=2.06
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Find the area under the standard normal curve between the given z-values. Round your answer to four decimal places, if necessary.
z1=−2.06, z2=2.06
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- Find the z-scores for which 97% of the distribution's area lies between -z and z. Click to view page 1 of the table. Click to view page 2. of the table. The z-scores are (Use a comma to separate answers as needed. Round to two decimal places as needed.)Find the area under the normal curve to the left of z= -1.56 plus the area under the normal curve to the right of z= 2.56. The combined area is?find the area to the left of a z-score of 1.13 A. 0.8708 B. 0.8907 C. 0.8485 D.0.1292
- Find the area under the normal curve between z= -2.23 and z= -1.22. Express your answer as a decimal. Round to 4 decimal places after the decimal point. Answer:Identify the z-score based on the area under the curve. Find the z-score where 95% (.95) of the curve is below this z-score and 5% (.05) is above. Find the z-scores between which 95% (.95) of the curve is located, with 2.5% (.025) is left in each tail.Find the area under the normal curve between z= -2.10 and z= -0.45.Express your answer as a decimal. Round to 4 decimal places after the decimal point. Answer:
- Find the z-score that has 6.3% of the distribution's area to its left. The z score is __________. Round to two decimal places as needed.Find the z-scores for which 15% of the distribution's area lies between -z and z. Click to view page 1 of the table. Click to view page 2 of the table. The z-scores are (Use a comma to separate answers as needed. Round to two decimal places as needed.) ntsSketch the normal curve. 1. Find the area between z= -1.5 and z= -2.5 2. Find the area between z= -1.35 and z=2.95 3. Find the area to the left of z= 2.32 4. Find the area to the right of z= -1.8
- Find the z-scores that correspond to the percentage of adult spiders that have carapace lengths between 11 mm and 12 mm. The percentage of adult spiders that have carapace lengths between 11 mm and 12 mm is equal to the area under the standard normal curve between negative 1.72−1.72 and negative 1.18−1.18. (Round to two decimal places as needed.)Find the z-scores for which 80% of the distribution's area lies between -z and z. Click to view page 1 of the table. Click to view page 2 of the table. The Z-scores are (Use a comma to separate answers as needed. Round to two decimal places as needed.) C(b) The figure to the right represents the normal curve with u= 266 days and o = 16 days. The area between x = 285 and x= 300 is 0.1007. Provide two interpretations of this area. Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals. Use ascending order.) O A. The proportion of human pregnancies that last less than or more than days is O B. The proportion of human pregnancies that last between and days is X 266 285 300 Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals. Use ascending order.) O A. The probability that a randomly selected human pregnancy lasts between and days is O B. The probability that a randomly selected human pregnancy lasts less than or more than days is
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