Find the area trapezoids: 14. 7. \70° 70% 5 10.6 5

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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Find the area of the following trapezoids:

### Finding the Area of Trapezoids

To find the area of a trapezoid, use the formula:
\[ \text{Area} = \frac{1}{2} \times (a + b) \times h \]
where \(a\) and \(b\) are the lengths of the bases, and \(h\) is the height.

Below are three trapezoids for which you are asked to find the area. 

#### Problem 7:
- **Bases**: \(14\) and \(10.6\)
- **Height**: The problem does not directly provide the height, and it uses two 70-degree angles and vertical lines to depict a possibly different scenario of calculation. However, under typical conditions using height would apply.

#### Problem 8:
- **Bases**: \(3\) and \(5\)
- **Height**: \(4\)

#### Problem 9:
- **Bases**: \(5\) and \(7\)
- **Height**: \(10\)

### Detailed Steps:

#### Problem 7:

This is a more complex trapezoid because it includes additional angle and side annotations. To find the height:
1. Understand the structure and the given dimensions effectively.
2. Use geometric properties or trigonometric ratios to determine the height, which requires considering given degrees.

#### Problem 8:

1. Add the bases: \(3 + 5 = 8\).
2. Multiply by the height: \(8 \times 4 = 32\).
3. Divide by 2: \( \frac{32}{2} = 16 \).

So, the area of trapezoid 8 is \( 16 \text{ square units} \).

#### Problem 9:

1. Add the bases: \(5 + 7 = 12\).
2. Multiply by the height: \(12 \times 10 = 120\).
3. Divide by 2: \( \frac{120}{2} = 60 \).

So, the area of trapezoid 9 is \( 60 \text{ square units} \).

Use these principles and calculations to find the area of each trapezoid. Practice helps in refining the understanding and application of these geometric concepts.
Transcribed Image Text:### Finding the Area of Trapezoids To find the area of a trapezoid, use the formula: \[ \text{Area} = \frac{1}{2} \times (a + b) \times h \] where \(a\) and \(b\) are the lengths of the bases, and \(h\) is the height. Below are three trapezoids for which you are asked to find the area. #### Problem 7: - **Bases**: \(14\) and \(10.6\) - **Height**: The problem does not directly provide the height, and it uses two 70-degree angles and vertical lines to depict a possibly different scenario of calculation. However, under typical conditions using height would apply. #### Problem 8: - **Bases**: \(3\) and \(5\) - **Height**: \(4\) #### Problem 9: - **Bases**: \(5\) and \(7\) - **Height**: \(10\) ### Detailed Steps: #### Problem 7: This is a more complex trapezoid because it includes additional angle and side annotations. To find the height: 1. Understand the structure and the given dimensions effectively. 2. Use geometric properties or trigonometric ratios to determine the height, which requires considering given degrees. #### Problem 8: 1. Add the bases: \(3 + 5 = 8\). 2. Multiply by the height: \(8 \times 4 = 32\). 3. Divide by 2: \( \frac{32}{2} = 16 \). So, the area of trapezoid 8 is \( 16 \text{ square units} \). #### Problem 9: 1. Add the bases: \(5 + 7 = 12\). 2. Multiply by the height: \(12 \times 10 = 120\). 3. Divide by 2: \( \frac{120}{2} = 60 \). So, the area of trapezoid 9 is \( 60 \text{ square units} \). Use these principles and calculations to find the area of each trapezoid. Practice helps in refining the understanding and application of these geometric concepts.
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