Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
Find the area of the following trapezoids:
![### Finding the Area of Trapezoids
To find the area of a trapezoid, use the formula:
\[ \text{Area} = \frac{1}{2} \times (a + b) \times h \]
where \(a\) and \(b\) are the lengths of the bases, and \(h\) is the height.
Below are three trapezoids for which you are asked to find the area.
#### Problem 7:
- **Bases**: \(14\) and \(10.6\)
- **Height**: The problem does not directly provide the height, and it uses two 70-degree angles and vertical lines to depict a possibly different scenario of calculation. However, under typical conditions using height would apply.
#### Problem 8:
- **Bases**: \(3\) and \(5\)
- **Height**: \(4\)
#### Problem 9:
- **Bases**: \(5\) and \(7\)
- **Height**: \(10\)
### Detailed Steps:
#### Problem 7:
This is a more complex trapezoid because it includes additional angle and side annotations. To find the height:
1. Understand the structure and the given dimensions effectively.
2. Use geometric properties or trigonometric ratios to determine the height, which requires considering given degrees.
#### Problem 8:
1. Add the bases: \(3 + 5 = 8\).
2. Multiply by the height: \(8 \times 4 = 32\).
3. Divide by 2: \( \frac{32}{2} = 16 \).
So, the area of trapezoid 8 is \( 16 \text{ square units} \).
#### Problem 9:
1. Add the bases: \(5 + 7 = 12\).
2. Multiply by the height: \(12 \times 10 = 120\).
3. Divide by 2: \( \frac{120}{2} = 60 \).
So, the area of trapezoid 9 is \( 60 \text{ square units} \).
Use these principles and calculations to find the area of each trapezoid. Practice helps in refining the understanding and application of these geometric concepts.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc9bce8c0-069b-44af-bdf7-a7daf1a8c7d3%2Fe108718e-8608-4493-8655-e1eafbfcba47%2F0dat9m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Finding the Area of Trapezoids
To find the area of a trapezoid, use the formula:
\[ \text{Area} = \frac{1}{2} \times (a + b) \times h \]
where \(a\) and \(b\) are the lengths of the bases, and \(h\) is the height.
Below are three trapezoids for which you are asked to find the area.
#### Problem 7:
- **Bases**: \(14\) and \(10.6\)
- **Height**: The problem does not directly provide the height, and it uses two 70-degree angles and vertical lines to depict a possibly different scenario of calculation. However, under typical conditions using height would apply.
#### Problem 8:
- **Bases**: \(3\) and \(5\)
- **Height**: \(4\)
#### Problem 9:
- **Bases**: \(5\) and \(7\)
- **Height**: \(10\)
### Detailed Steps:
#### Problem 7:
This is a more complex trapezoid because it includes additional angle and side annotations. To find the height:
1. Understand the structure and the given dimensions effectively.
2. Use geometric properties or trigonometric ratios to determine the height, which requires considering given degrees.
#### Problem 8:
1. Add the bases: \(3 + 5 = 8\).
2. Multiply by the height: \(8 \times 4 = 32\).
3. Divide by 2: \( \frac{32}{2} = 16 \).
So, the area of trapezoid 8 is \( 16 \text{ square units} \).
#### Problem 9:
1. Add the bases: \(5 + 7 = 12\).
2. Multiply by the height: \(12 \times 10 = 120\).
3. Divide by 2: \( \frac{120}{2} = 60 \).
So, the area of trapezoid 9 is \( 60 \text{ square units} \).
Use these principles and calculations to find the area of each trapezoid. Practice helps in refining the understanding and application of these geometric concepts.
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