Find the area of the surface generated when the given curve is revolved about the given axis. y = 12 + /144 - x2 between the points (12,12) and 5/23 25 ' 2 about the y-axis 2
Find the area of the surface generated when the given curve is revolved about the given axis. y = 12 + /144 - x2 between the points (12,12) and 5/23 25 ' 2 about the y-axis 2
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.1: Parabolas
Problem 40E
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![Find the area of the surface generated when the given curve is revolved about the given axis.
´5/23 25
y = 12 + /144 - x2 between the points (12,12) and
2
about the y-axis
2
The surface area is square units.
(Type an exact answer, using n as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff51f36fc-1b5a-4c78-9e0a-e2ee16ae8054%2F58d4a167-6ea4-4348-88d4-9cbf537950af%2F1b44mm6_processed.png&w=3840&q=75)
Transcribed Image Text:Find the area of the surface generated when the given curve is revolved about the given axis.
´5/23 25
y = 12 + /144 - x2 between the points (12,12) and
2
about the y-axis
2
The surface area is square units.
(Type an exact answer, using n as needed.)
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