Find the area of the surface generated by revolving the curve y = √2x-x², 0.5≤x≤ 1.75, about the x-axis. Set up the integral that gives the area of the given surface. 1.75 √ 22x-x²1+ 0.5 S= (1-x)² 2x-x dx The area of the surface is square units. (Type an exact answer, using as needed.) Par

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