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- Draw the graph and highlight the area of ± 2 standard deviations.The histogram of the number of hours of sleep Stat 100 students reported getting each night roughly follows the normal curve with an average of 7.0 hours and a SD of 1.2 hours. a. Approximately 68% of the students sleep between hours and hot (Put the smaller number first) 提交答案|Tries 0/5 b. Approximately 95% of the students sleep between hours and hours. (Put the smaller number first) 提交答案| Tries 0/5 c. If a student sleeps 5.2 hours per night what percent of the people sleep more than her? Do the problem in steps: I. First, find the Z score = 提交答案|Tries 0/3 ii. Now, move the red vertical line on the following graph to the correct Z score by clicking and dragging the mouse. If you are using a touch screen, touch and then slide the region around the vertical line 1.00 Shade the region representing the percent of people who sleep more than her: Shade the region under the normal curve to the O left of the red vertical line O right of the red vertical lineGiven a normally distributed data, what is the area of the region less than one standard deviationabove the mean and more than three standard deviations above the mean?
- Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the probability of a bone density test score greater than 3.85. Sketch the region. Choose the correct graph below. O A. -3.85 B. The probability of a bone density test score greater than - 3.85 is (Round to four decimal places as needed.) 3.85 ^ 3.85 A -3.85Explain, whether the data can be calculated if the hypergeometric distribution is not known the number of populations?The weight of cereal boxes (y) follows a normal distributed with a variance of 0.1 squared ounces. If the average is 15.8 ounces, then P(y < 16) = If the average is 16.5 ounces, then P(y > 16.2)
- Please show the complete solutionPlease help not gradedFind the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. A graph with a bell-shaped curve, divided into 3 regions by 2 lines from top to bottom, one on the left side and one on the right side. The region between the lines is shaded. Moving from left to right, the x-axis below the first line is labeled 75. The x-axis below the second line is labeled 110.
- Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma. Over a period of months, an adult male patient has taken eight blood tests for uric acid. The mean concentration was = 3.5 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with σ = 1.85 mg/dl. Find a 95% confidence interval for the population mean concentration of uric acid in this patient’s blood. What is the margin of error? What conditions are necessary for your calculations? Interpret results in the context of this problem. Sample Size Find the sample size necessary for a 95% confidence level with maximal margin of error E=1.10 for the mean concentration of uric acid in this patient’s blood.If the mean of grades in statistics = 65 and the variance : 400 , then the Z score of grade 50 ="Durable press" cotton fabrics are treated to improve their recovery from wrinkles after washing. "Wrinkle recovery angle" measures how well a fabric recovers from wrinkles. Higher is better. Here are data on the wrinkle recovery angle (in degrees) for two types of treated fabrics: Permafresh Hylite 15 17 12 14 13 16 16 15 14 18 A manufacturer wants to know how large is the difference in mean wrinkle recovery angle. Give a 98% confidence interval for the difference in mean wrinkle recovery angle: [three decimal accuracy] [three decimal accuracy]